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2 years ago

∠A and \angle B∠B are complementary angles. If m\angle A=(2x+30)^{\circ}∠A=(2x+30)

Mathematics

2 answers:

Brut [27]2 years ago

7 0

Answer:

∠A = 48

Step-by-step explanation:

∠A + ∠B = 90 ( Complementary angles)

2x + 30 + 6x - 12 = 90

Combine like terms

2x + 6x +30 - 12 = 90

8x + 18 = 90 {subtract 18 form both sides}

8x = 90 - 18

8x = 72 {Divide both sides by 8}

8x/8 = 72/8

x = 9

∠A = 2x + 30

= 2*9 + 30

= 18 + 30

∠A = 48

egoroff_w [7]2 years ago

6 0

Answer:

x =21

Step-by-step explanation:

So we know that:

And that the two angles are vertical angles.

Since they are vertical angles, their measurements are equivalent. Thus, to find x, set the equations equal to each other:

Now, solve for x. Add 30 to both sides. The left side cancels:

Now, subtract 2x from both sides. The right cancels:

Thus, the value of x is 21.

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How to graph 9x+5y=-45

lilavasa [31]

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2 years ago

HELP A GIRL OUT

3241004551 [841]

The numbers are 9 and 27.

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2 years ago

<img src="https://tex.z-dn.net/?f=n%20%3D%2020" id="TexFormula1" title="n = 20" alt="n = 20" align="absmiddle" class="latex-form

devlian [24]

Answer:

s=10

Step-by-step explanation:

Basically, the range rule-of-thumb is that the range is generally about four times the standard deviation.

First, we find the range:

Range=Maximum-Minimum

Range=100-60

Range=40

Next, divide the range by 4 to get the standard deviation

Range=4(Standard Deviation)

40=4(Standard Deviation)

10=Standard Deviation

Therefore, s=10, which is the standard deviation

6 0

2 years ago

Read 2 more answers

Factor as the product of two binomials X^2 +8x +12 = ?

aksik [14]

The answer to this is (x+6)(x+2)

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2 years ago

Please can anyone send a question in law of indices I really need it now

DaniilM [7]

Answer:

I think this is a pretty good question of law of indices

Step-by-step explanation:

Given that

$(9^p)(27^q)=3^n\\$

a) express n in terms of p and q ,

b) hence if p = 1 and q = 2 find the value of n

Solution to part a)

$(9^p)(27^q)=3^n\\\\$

Simplify the equation and how do we do that? As we can see that 9 can also be written as 3^2 and 27 can be written as 3^3 we can rewrite the following equation like this,

$(3^2)^p(3^3)^q=3^n\\$