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gizmo_the_mogwai [7]
3 years ago
14

Solve the equation: 2x=4

Mathematics
2 answers:
vodomira [7]3 years ago
6 0

Answer:

X= 2

Step-by-step explanation:

nekit [7.7K]3 years ago
4 0

Answer:

x=2

Step-by-step explanation:

2x=4

x=4/2

x=2

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KengaRu [80]
You can do this 2 ways, one is knowing the special right triangles called triplets. An example of a triplet would be 3-4-5 where the largest value is the hypotenuse. In this example, the other 2 sides are 3 and 4 and the missing side is the hypotenuse, so using the knowledge of triplets, we can find that the hypotenuse is 5.

algebraically, we can use the Pythagorean theorem; a^2+b^2=c^2 where a and b are the opposite and adjacent and where c is the hypotenuse. We can then substitute in the values to get : 3^2 + 4^2 = c^2. When simplified, we get 9+16=c^2. Simplify further, and get 25=c^2. Now we Square root both sides to solve for C. Finally, we get C=5. Your missing side is 5.
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2 years ago
Miss Jones wants to buy at least 10 books. Each paperback book costs an average
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Hello guys not quite sure this
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2 years ago
Which statements are true about reflections? Check all that apply.
maria [59]

Answer:

A, B, C, D, F

Step-by-step explanation:

<em>A. An image created by a reflection will always be congruent to its pre-image. </em>

Congruent means identical or similar. The orientation, size, and shape of the pre-image are not changed after a reflection- therefore, the pre-image and image are congruent.

<em>B. An image and its pre-image are always the same distance from the line of reflection.</em>

When a pre-image is flipped across the line of reflection, both figures are perfectly symmetrical. Nothing has changed aside from orientation and location on the graph. The number of units between the figures and the line of reflection should remain unchanged.

<em>C. If a point on the pre-image lies on the line of reflection, the image of that point is the same as the pre-image.</em>

When you reflect a pre-image with a point that lies on the line of reflection, that point will stay on the line of the reflection as the rest of the figure is flipped.

I will explain these two answers together since they have similar explanations.

<em>D. The line of reflection is perpendicular to the line segments connecting corresponding vertices.</em>

<em>F. The line segments connecting corresponding vertices are all parallel to each other.</em>

In a reflection, the horizontal or vertical (depending on the line of reflection, y-axis or x-axis) coordinates are altered. However, if one were to draw an imaginary line connecting the corresponding vertices, both the image and pre-image are parallel and perpendicular.

I hope this helped, good luck on your work/test!

7 0
2 years ago
Line l is tangent to the graph of y= x - x²/500 at point Q &amp; it crosses the y-axis at (0, 20)
insens350 [35]
A. Equation of line l: y = mx + 20 where m = y' = 1- (1/250)x 

At the point Q, The equation of the line equals the equation of the parabola. 

So (1-x/250)x + 20 = x - x^2/500 

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<span>Equation of line L is y = 3/5x + 20 
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C)  If a spotlight is located at the x intercept of line L (-33 1/3,0), its light will go only above line L past the point where line L is tangent to the hill at (100,80) because the hill blocks the light below the tangent line. 

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</span>
--------------------------

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Name non equivalent fractions
garri49 [273]
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