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gizmo_the_mogwai [7]
3 years ago
14

Solve the equation: 2x=4

Mathematics
2 answers:
vodomira [7]3 years ago
6 0

Answer:

X= 2

Step-by-step explanation:

nekit [7.7K]3 years ago
4 0

Answer:

x=2

Step-by-step explanation:

2x=4

x=4/2

x=2

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The table shows values for functions f(x)and g(x)
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Answer:

x= -1 and x =0

Step-by-step explanation:

all work is shown and pictured

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Pick the correct inequality.<br><br> A . <br> B. <br> C. <br> D .
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The answer is B x is greater than or equal to -6
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Y=4x-2tan(x), (-pi/2,pi/2)<br> which are the relative min and max?
Jlenok [28]

relative max  = pi -2

relative min   = -2 pi

Step-by-step explanation:

y= 4x- 2tan(x), (-pi/2,pi/2)

To find relative max and min,

According to mathematical procedure to find relative max and relative min,

the following procedure should be carry out.

Derivating equation with respect to x,

          \frac{dy}{dx} =\frac{d}{dx}  (4\times x -2 \times tan x).....(1)

Equating equation (1) to Zero,

We get,

           0 =\frac{d}{dy}  (4\times x -2 \times tan x)

           0 =  4 -2 \times sec^{2}  x

           4 = 2 \times sec^{2}  x

           2 = sec^{2}  x

           x= \frac{\pi }{4}....stationary point

There are total three points

1. -pi/2      2. pi/2      3. pi/4

checking local min and local max

first considering -pi/2;

                   \frac{d^{2}y  }{dx^{2} } =\frac{d^{2} }{dx^{2} }  (4\times x -2 \times tan x)...(2)

putting x= pi/4 in equation (2),

we get,      

                   \frac{d^{2}y  }{dx^{2} } = -4 <0      

So, we have local max at x=pi/4

by putting value of x in equation (1);

we get,

                 y =   4\times (\pi /4 ) -2 \times tan (\pi /4 )

                y = \pi - 2  .... is maximum point.

Similarly,  at  x= -pi/ 2,

                  \frac{d^{2}y  }{dx^{2} } = 1 >0

So, we have local min at x=-pi/2

by putting value of x in equation (1);

we get,

                 y =   4\times (-\pi /2 ) -2 \times tan (-\pi /2 )

                 y =  -2 \times \pi.... is minimum point

       

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3 years ago
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In a study of the accuracy of fast food​ drive-through orders, one restaurant had 40 orders that were not accurate among 307 ord
klemol [59]

Answer:

We conclude that the rate of inaccurate orders is greater than ​10%.

Step-by-step explanation:

We are given that in a study of the accuracy of fast food​ drive-through orders, one restaurant had 40 orders that were not accurate among 307 orders observed.

Let p = <u><em>population proportion rate of inaccurate orders</em></u>

So, Null Hypothesis, H_0 : p \leq 10%     {means that the rate of inaccurate orders is less than or equal to ​10%}

Alternate Hypothesis, H_A : p > 10%      {means that the rate of inaccurate orders is greater than ​10%}

The test statistics that will be used here is <u>One-sample z-test</u> for proportions;

                          T.S.  =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of inaccurate orders = \frac{40}{307} = 0.13

           n = sample of orders = 307

So,<u><em> the test statistics</em></u> =  \frac{0.13-0.10}{\sqrt{\frac{0.10(1-0.10)}{307} } }  

                                    =  1.75

The value of z-test statistics is 1.75.

<u>Also, the P-value of the test statistics is given by;</u>

            P-value = P(Z > 1.75) = 1 - P(Z \leq 1.75)

                          = 1 - 0.95994 = <u>0.04006</u>

Now, at 0.05 level of significance, the z table gives a critical value of 1.645  for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 1.75 > 1.645, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the rate of inaccurate orders is greater than ​10%.

8 0
3 years ago
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