Answer:
वि स्कुल माध्यामिक विद्यालय निम्न माध्यामिक विद्यालय व्यवस्थापन समिति सम्पादन र प्रकाशनमा बुटवलबाट निस्कने एक्सरे साप्ताहिकमा एक पटक साप्ताहिकमा छापिएको थियो। प्रकाशित
Answer:
1st integer=x
2nd integer=x+1
3rd integer=x+2
4th integer=x+3
2(x +(x+2))= 3(x+1) +11
solve
2 (2x +2) = 3x + 3 + 11
4x + 4 = 3x + 14
-3x-4 =-3x -4
x=10
1st integer=10
2nd integer=11
3rd integer=12
4th integer=13
Step-by-step explanation:
hopefully this helped
Hello from MrBillDoesMath!
Answer:
5 x^3 + 15 x^2 + 15 x + 5 , none of the provided choices
Discussion:
f(x) = 5 x^3
g(x) = x+ 1
=>
(f•g)(x) =
f(g(x)) =
f(x+1) =
5 * (x+1)^3 =
5 x^3 + 15 x^2 + 15 x + 5
which is none of the provided answers.
Thank you,
MrB
Answer:
y=3x+1, or the second option
Step-by-step explanation:
We can see on the graph the line converges with the y-axis at (0, 1), so we can cross out the last two answers. Then we can also see that the slope is 3 on the graph and an equation that has x^2 must be a parabola. The answer is then narrowed down to the second option.
Where’s the graph or whatever???
