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nika2105 [10]
3 years ago
9

What is the present value of ​$3,000 per year for 9 years discounted back to the present at 10 ​percent?

Mathematics
1 answer:
Studentka2010 [4]3 years ago
3 0

Answer:

$17,277.07

Step-by-step explanation:

Present value of annuity is the present worth of cash flow that is to be received in the future, if future value is known, rate of interest is r and time is n then PV of annuity is

PV of annuity = \frac{P[1-(1+r)^{-n}]}{r}

                      = \frac{3000[1-(1+0.10)^{-9}]}{0.10}

                      = \frac{3000[1-(1.10)^{-9}]}{0.10}

                      = \frac{3000[1-0.4240976184]}{0.10}

                      = \frac{3000(0.5759023816)}{0.10}

                      = \frac{1,727.7071448}{0.10}

                      = 17,277.071448 ≈ $17,277.07

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Pounds of beef and potatoes are in ratio or proportion of \frac{1}{3} .

<u>Step-by-step explanation:</u>

Correct Question: A recipe for beef stew calls for 1 pound of beef and 3 potatoes. The recipe is doubled to include 2 pounds of beef and 6 potatoes. Which proportion represents the situation?

We have , A recipe for beef stew calls for 1 pound of beef and 3 potatoes , i.e.

Number of beef stew calls = 1

Number of potatoes = 3

Now , The recipe is doubled to include 2 pounds of beef and 6 potatoes i.e. for every 2 pounds of beef we have 6 potatoes

⇒ 2/6

⇒ \frac{2}{6}

⇒ \frac{2}{2(3)}

⇒ \frac{1}{3}

Therefore , Pounds of beef and potatoes are in ratio or proportion of \frac{1}{3} .

4 0
3 years ago
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y = 3(4) - 4
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Step-by-step explanation:

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We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.

We know that area of rectangle is width times length.

To find the area of the given rectangle we will multiply both side lengths as:

\text{Area of rectangle}=\text{Width}\times \text{Length}

\text{Area of rectangle}=\frac{3}{4}\text{ yard}\times\frac{5}{6}\text{ yard}

\text{Area of rectangle}=\frac{3}{4}\times\frac{5}{6}\text{ yard}^2

\text{Area of rectangle}=\frac{1}{4}\times\frac{5}{2}\text{ yard}^2

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Therefore, the area of the given rectangle would be \frac{5}{8} square yards.

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