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3 years ago

-0.3x2 + 2x + 3 What is this equation in a table ?

Mathematics

1 answer:

den301095 [7]3 years ago

7 0

Answer:

Here

Step-by-step explanation:

Just pick numbers and substitute it into the equation for x

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How do you solve 2r^2+2r-24=0 using the quadratic formula ?

kramer

2r2+2r−24=0

Step 1: Factor left side of equation.

2(r−3)(r+4)=0

Step 2: Set factors equal to 0.

r−3=0 or r+4=0

r = 3 or r = −4

7 0

3 years ago

(picture included) will mark brainliest

Anarel [89]

Answer:

1. A

2. C

3. B

Step-by-step explanation:

1. we can create an equation y = 48x + 96

if we plug in 1 we get 144

2. we can create an equation y = 10x to represent how much battery you will lose every hour

if we plug in 5 to x, we get y = 50

so we get the plot point: (5, 50)

3. process of elimination

5 0

3 years ago

12:53:34

Drupady [299]

Answer:

Reference Point

Step-by-step explanation:

The answer is reference point. This is because reference point is used to determine if an object is in motion or if it has changed is direction.

Thus, reference point has to be a value of zero for us to use it to determine if an object has moved.

8 0

3 years ago

Can anyone help me out plz and thank you

BARSIC [14]

Wsg is it asking for

4 0

3 years ago

Which students line segments have a midpoint of (-1,4)? Select all that apply A. Student 1 B. Student 2 C. Student 3 D. Student

SashulF [63]

Answer:

C. Student 3

E. Student 5

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

Verify the midpoint of each student

student 1

we have the endpoints

(-9,0) and (11,-8)

substitute in the formula

$M(\frac{-9+11}{2},\frac{0-8}{2})$

$M(1,-4)$

The midpoint is not (-1,4)

student 2

we have the endpoints

(-6,-1) and (4,-7)

substitute in the formula

$M(\frac{-6+4}{2},\frac{-1-7}{2})$

$M(-1,-4)$

The midpoint is not (-1,4)

student 3

we have the endpoints

(-5,2) and (3,6)

substitute in the formula

$M(\frac{-5+3}{2},\frac{2+6}{2})$

$M(-1,4)$

The midpoint is equal to (-1,4)

student 4

we have the endpoints

(-3,10) and (5,-2)

substitute in the formula

$M(\frac{-3+5}{2},\frac{10-2}{2})$

$M(1,4)$

The midpoint is not (-1,4)

student 5

we have the endpoints

(0,-3) and (-2,11)

substitute in the formula

$M(\frac{0-2}{2},\frac{-3+11}{2})$

$M(-1,4)$

The midpoint is equal to (-1,4)

therefore

Student 3 and student 5

3 0

4 years ago