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kozerog [31]
2 years ago
8

On three consecutive flips of a coin, what is the probability that all three produce the

Mathematics
1 answer:
natulia [17]2 years ago
7 0
Probability of 1/4

2 possibilities x 2 possibilities x 2 possibilities = 8 total possibilities:
Heads, Heads, Heads
Heads, Heads, Tails
Heads, Tails, Tails
Heads, Tails, Heads
Tails, Tails, Tails
Tails, Tails, Heads
Tails, Heads, Heads
Tails, Heads, Tails

2 of which result in all of the same outcome:
Heads, Heads, Heads
Tails, Tails, Tails

2 results/ 8 possibilities = 2/8 = 1/4
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I need help with this review question​
WINSTONCH [101]

Answer:

Δ MAN

reason: ASA

Step-by-step explanation:

if you look at the congruency marks you can see that ∡F ≅ ∡A and we know that ∡N ≅ ∡N

markings also show us that sides UF ≅ MA

therefore, we know two angles and one side for each triangle

6 0
2 years ago
What is the inverse of f(x)=2-2x
juin [17]
In the usual sense, it has no inverse function. Since it is not an injection (f(0)=f(2)=0), an inverse function would have to map 0 both to 0 and 2, and that’s impossible.

However, if you restrict the domain to [1,+oo> (to make it injective), and the codomain to [-1,+oo> (to make it surjective), then it has an inverse function, given by g(y)=1+sqrt(y+1).
6 0
2 years ago
A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe
Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid  

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

Volume=\frac{1}{2} (b_{1}+4+2x)h X H

Volume=\frac{1}{2} (4+4+2x)h X 16

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

V=64h+16h(\frac{h}{4})

V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}

h=3m,

dV/dt=25cm/min=0.25 m/min

0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0
3 years ago
Write 504 as a product of powers of its prime factor
mamaluj [8]
Answer of the same question here; brainly.com/question/1543229
7 0
3 years ago
Help I’ll give brainlist helpoppspspapappa
sweet [91]

Answer:

22

Step-by-step explanation:

51-29 is 22

6 0
3 years ago
Read 2 more answers
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