Answer:
What kind of help you want ?
Answer:
5 hours
Step-by-step explanation:
75 + 55x = 350
75 - 75 + 55x = 350 - 75
55x = 275
x = 5
First you have to know how many inches are in a square cm and then the answer that you get for that first part you just multiply that by what you have but dont use a calcutor cause it wont give you the right answer because i had this before and i got it correct
Yes so i do need to doing the times and multipics then get a fraction then u will get tot eh answer
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
