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Dafna1 [17]
2 years ago
11

Consider a group of 1,000 newborn infants. One hundred (100) infants were born with serious birth defects, and 20 of these 100 d

ied during the first year of life. Ninety (90) of the 900 remaining infants without any birth defects also died during the first year of life. Calculate the prevalence of serious defects in this population at the time of birth.
Mathematics
1 answer:
kozerog [31]2 years ago
8 0

Answer:

The prevalence of serious defects in this population at the time of birth is 10%.

Step-by-step explanation:

The prevalence of serious defects is the number of infants that were born with seriours birth defects divided by the total number of infants born.

In this problem, we have that:

There were 1000 newborn infants.

100 infants were born with serious birth defects.

Calculate the prevalence of serious defects in this population at the time of birth.

This is:

P = \frac{10}{100} = 0.1

The prevalence of serious defects in this population at the time of birth is 10%.

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aliya0001 [1]

Answer:

P-value =  0.4846

Step-by-step explanation:

We are given the following in the question:

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Sample mean, \bar{x} = 4.35

Sample size, n = 51

Alpha, α = 0.05

Sample standard deviation, s = 3.88

First, we design the null and the alternate hypothesis

H_{0}: \mu = 4.73\\H_A: \mu \neq 4.73

We use Two-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{4.35 - 4.73}{\frac{3.88}{\sqrt{51}} } = -0.699

Now, z_{critical} \text{ at 0.05 level of significance } = \pm 1.96

We can calculate the p-value with the help of standard normal table.

P-value =  0.4846

Since the p-value is higher than the significance level, we fail to reject the null hypothesis and accept it.

We conclude that this college has same drinking habit as the college students in general.

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3 years ago
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Answer:

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Sandra throws an object straight up into the air with an initial velocity of 38 ft/s from a platform that is 30 ft above the gro
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Answer:

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Step-by-step explanation:

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In this case, the initial postion is a platform 30ft above ground so h0=+30

The initial velocity is 38 ft/s straight up into the air so v0=+38

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Simplifying 8t2-19t-15=0

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As time cannot be -ve, t=3s. The answer is C.

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Answer:

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Step-by-step explanation:

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Answer:

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