Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)

=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Answer:
9
Step-by-step explanation:
if you mean -3.2x+9 then the answer is 9 because you plug in 0 into x and solve the equation, you get the x intercept
The correct option is (B) 4x^2 + 18x + 18
Explanation:
The area is given as:
(3+2x)(6+2x)
To find the polynomial just simplify it.
3(6+2x) + 2x(6+2x)
18 + 6x + 12x + 4x^2
4x^2 + 18x + 18
Answer:
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