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elixir [45]
3 years ago
13

What is the value of K in the equation 8 + 2k = 4k + 4

Mathematics
2 answers:
11111nata11111 [884]3 years ago
8 0
8+2k=4k+4
8-4=4k-2k                   I placed the like terms on each side.
4=2k                           Simplify
4/2=k                          Leave the variable a side
2 = k
Viktor [21]3 years ago
4 0
Step 1. Subtract 2k from both sides
8 = 4k + 4 - 2k
Step 2. Simplify 4k + 4 - 2k to 2k + 4
8 = 2k + 4
Step 3. Subtract 4 from both sides
8 - 4 = 2k
Step 4. Simplify 8 - 4 to 4
4 = 2k
Step 5. Divide both sides by 2
4/2 = k
Step 6. Simplify 4/2 to 2
2 = k
Step 7. Switch sides
Your answer is k = 2

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harina [27]

answer:

C. 16

explanation:

when x is 0, the y-intercept is 8

coordinates: (0,8) and (4,6)

slope:

\sf \frac{y2-y1}{x2-x1}

\sf \frac{6-8}{4-0}

\sf \frac{-2}{4}

\sf -\frac{1}{2}

equation:

\sf y = mx +b    [ where m is slope and b is y-intercept ]

y = \sf -\frac{1}{2}x +8

solve for x-intercept:

note: zeros of a function are the values of x when f(x) is equal to 0

y = \sf -\frac{1}{2}x +8

0= \sf -\frac{1}{2}x +8

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\sf x = 16

3 0
2 years ago
Read 2 more answers
What is the greatest common factor of 9x^{2}y9x 2 y and 5x^{4}y^{2}5x 4 y 2 ?
Musya8 [376]
ANSWER

The greatest common factor is
{x}^{2} y

EXPLANATION

We want to find the greatest common factor of

9 {x}^{2} y

and

5 {x}^{4}  {y}^{2}

The prime factorizations are;


9 {x}^{2} y =  {3}^{2}  \times  {x}^{2}  \times y


and


5 {x}^{4}  {y}^{2}  = 5 \times  {x}^{4}  \times  {y}^{2}


The product of the least powers of the common factors is the greatest common factor.


=  {x}^{2} y
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Answer:

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Step-by-step explanation:

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