All categories

3 years ago

What is the value of K in the equation 8 + 2k = 4k + 4

Mathematics

2 answers:

11111nata11111 [884]3 years ago

8 0

8+2k=4k+4
8-4=4k-2k I placed the like terms on each side.
4=2k Simplify
4/2=k Leave the variable a side
2 = k

Viktor [21]3 years ago

4 0

Step 1. Subtract 2k from both sides
8 = 4k + 4 - 2k
Step 2. Simplify 4k + 4 - 2k to 2k + 4
8 = 2k + 4
Step 3. Subtract 4 from both sides
8 - 4 = 2k
Step 4. Simplify 8 - 4 to 4
4 = 2k
Step 5. Divide both sides by 2
4/2 = k
Step 6. Simplify 4/2 to 2
2 = k
Step 7. Switch sides
Your answer is k = 2

You might be interested in

A sports store sold a total of 59 footballs and soccer balls last weekend. Soccer balls cost $12 and footballs costs $18. If tot

lidiya [134]

Answer:ededikfgi34

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the value of s in rectangle

Sphinxa [80]

Answer:

s + 1 = 2s

<u></u>

6 0

3 years ago

PLEASE HELP ME ASAP ILL MARK BRIANLIEST!!!!!!!!! ANSWER THE QUESTIONS AND DO THE STEPS TOO PLEASEE

Anon25 [30]

Answer:

1). t ≥ - $\frac{3}{2}$

2). k ≥ $\frac{16}{3}$

3). y < - $\frac{1}{2}$

4). b > $\frac{250}{9}$

5). w ≤ 0

Step-by-step explanation:

1). $14(\frac{1}{2}-t)\leq 28$

$\frac{14}{14}(\frac{1}{2}-t)\leq \frac{28}{14}$

$\frac{1}{2}-t\leq 2$

$-t\leq 2-\frac{1}{2}$

$-t\leq \frac{3}{2}$

t ≥ - $\frac{3}{2}$

2). 15k + 11 ≤ 18k - 5

15k - 18k ≤ -5 - 11

-3k ≤ - 16

3k ≥ 16

k ≥ $\frac{16}{3}$

3). 44y > 11 + 88y - 22y

44y > 11 + 66y

44y - 66y > 11

-22y > 11

22y < -11

$\frac{22y}{22}$

y < $-\frac{1}{2}$

4). $\frac{7}{9}(b - 27) > \frac{49}{81}$

$\frac{7}{9}(b - 27)\times \frac{9}{7} > \frac{49}{81}\times \frac{9}{7}$

(b - 27) > $\frac{7}{9}$

b > $\frac{7}{9}+27$

b > $\frac{250}{9}$

5). 11w - 8w ≥ 14w

3w - 14w ≥ 0

-11w ≥ 0

w ≤ 0

7 0

3 years ago

M is the incenter of triangle ABC. Find the lengths of MD and DC. (Look at pic)

Deffense [45]

Answer:

Part 1) $MD=9\ units$

Part 2) $DC=12\ units$

Step-by-step explanation:

Step 1

Find the length of MD

we know that

The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle

In this problem

$MD=ME=MF$ ------> is the radius of a circle inscribed inside the triangle