Answer:
As follows,
Step-by-step explanation:
Find the attachment.
Distance of PQ=√13
Distance of QR=√13
Distance of PR=√26
Thus, PQR is an isosceles triangle.
Distance of MN=√(16+(a-2)^2)
16=16+a^2-4a+4
a^2-4a+4=0
a=2
Distance of RS=√(9+(b+1)^2)
25=9+b^2+2b+1
b=3 or -5
Distance of RS=√(9+(-1-c)^2)
18=9+c^2 + 2 c + 1
c=-4,2
The squared root to all your problems show here and now when needed
the correct answer is False
Answer:
Step-by-step explanation:
Diameter:
A line passing through the center of the circle touching the circle at two points, is called diameter.
OR
The chord passing through the center is diameter.
It is double of the radius.
so,
Diameter = (2) (Radius of the circle)
Radius:
Diameter divided by 2.
OR half of the diameter is called radius.
So,
Radius = (1/2) (diameter of the circle)
Area of a circle:
Area of a circle =πr^2
Using π=3.14
Area ≈ (3.14) (radius squared)
Circumference of a cricle:
It is equal to 2πr
If π=3.14, then 2π=6.28
Circumference ≈ (6.28) (radius of the circle)
Answer:
the answer should be 8
Step-by-step explanation:
8-5=3
3/3=1
