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2 years ago

4. In the expression -9x-2 +7, what is the coeffcent of x? A.-9 B.-2 C.7 D.9

1 answer:

3 0

A coefficient is the number before the variable so the coefficient of x would be number before the x. the number before x is A.-9

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Which equation is correct?

nika2105 [10]

Answer:

52 x 7= 50 x 7 + 2 x 7

Step-by-step explanation:

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2 years ago

How to solve this equation: ax² - 5x + 2 = 0

swat32

Answer:

$x=\frac{5(+/-)\sqrt{25-8a}} {2a}$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$ax^{2} -5x+2=0$

$a=a\\b=-5\\c=2$

substitute in the formula

$x=\frac{5(+/-)\sqrt{-5^{2}-4(a)(2)}}{2a}$

$x=\frac{5(+/-)\sqrt{25-8a}} {2a}$

6 0

2 years ago

PLEASE HELP I'LL LEAVE THANKS:)

miskamm [114]

1 to 6!!!!!!!!!!!!!!!!!!

8 0

3 years ago

Olivia has an average score 90 on her five French tests if she earns a score of 98 on the sixth test what will he average score

SVETLANKA909090 [29]

Answer:

91.33

Step-by-step explanation:

90x5=450, add 98 to get 548. Since there are 6 tests, divide 548 by 6 and you get 91.33

7 0

3 years ago

The sutton police department must write, on average, 6 tickets a day to keep department revenues at budgeted levels. suppose the

lakkis [162]

The Poisson distribution defines the probability of k discrete and independent events occurring in a given time interval.
If λ = the average number of event occurring within the given interval, then
$P(k \, events) = e^{-\lambda } ( \frac{\lambda ^{k}}{k!} )$

For the given problem,
λ = 6.5, average number of tickets per day.
k = 6, the required number of tickets per day
The Poisson distribution is
$P(k \, tickets/day)=e^{-6.5} ( \frac{6.5 ^{k}}{k!} )$
The distribution is graphed as shown below.

Answer:
The mean is λ = 6.5 tickets per day, and it represents the expected number of tickets written per day.
The required value of k = 6 is less than the expected value, therefore the department's revenue target is met on an average basis.

8 0

3 years ago