Question

How to solve this equation: ax² - 5x + 2 = 0

Answer 1

Answer:

$x=\frac{5(+/-)\sqrt{25-8a}} {2a}$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$ax^{2} -5x+2=0$

so

$a=a\\b=-5\\c=2$

substitute in the formula

$x=\frac{5(+/-)\sqrt{-5^{2}-4(a)(2)}}{2a}$

$x=\frac{5(+/-)\sqrt{25-8a}} {2a}$