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FinnZ [79.3K]
3 years ago
10

Plz help!!! Anyone! Plz help me with this question.

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
7 0

Negative means less.

Positive means more.

as a negative # moves farther away from 0, it becomes smaller.

i.e.

-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7

-5 less than 7.

bazaltina [42]3 years ago
5 0

Answer:

it is greater  because positive numbers, either rational or not, are greater than the negative numbers, either rational or not.



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Which answer choice is equivalent to the expression below?
Bess [88]

Answer:

the answer would be -13n-23

Step-by-step explanation:

first you want to distribute the brackets

-7(2+n) = -14-7n

+(-9-6n)

-9-6n

-14-7n-9-6n

combine the n value with an n value and an integer that doesn't have an n value

-7n-6n-14-9

= -13n-23

8 0
3 years ago
Write and solve a proportion to answer the question. 3/4 is 60% of what number?
Ganezh [65]


3/4 equals .75, and 60% equals .60. Therefore, we can set up an equation. .75=.60x, where x is the number we are looking for.

Divide each side by .60 to get the variable by itself. .75/.60= 1.25.


Hope this helped!!! :)

6 0
3 years ago
(x^2 - x^(1/2))/(1-x^(1/2))
Levart [38]
\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }-{ x }^{ \frac { 3 }{ 2 }  }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x
3 0
3 years ago
Read 2 more answers
Pls help. Write an equation where the solution is 2.
alexira [117]

Answer:

Step-by-step explanation:

x = 2 works lol

but if you want a more complicated one:

4x - 4 = 4

there's infinite equations

7 0
3 years ago
Helpp me with this please!
Dmitry [639]
It’s CED hope this helps
6 0
3 years ago
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