Question

What is the absolute value of the complex number -4-√2i

Answer 1

Answer:

$\sqrt[3]{2}$

Step-by-step explanation:

If the complex number is given in the form of  ( a+bi)

Then absolute value of the complex number will be = $\sqrt{a^{2}+b^{2} }$

Now the given complex number is ( $-4 \sqrt[-i]{2}$

So in this number a = ( -4 ) and b = $\sqrt[-]{2}$

Therefore, absolute value will be = $\sqrt{(-4)^{2}+(\sqrt[-]{2})^{2}}$

                                                      = $\sqrt{16+2}$

                                                      = $\sqrt{18}$

                                                      = $\sqrt{9*2}$

                                                     = $\sqrt[3]{2}$

So absolute value will be $\sqrt[3]{2}$.

Answer 2

Answer:

3√2

Step-by-step explanation:

Recall that "absolute value" often denotes "distance."  We could apply the distance formula here, obtaining

distance = absolute value of -4 - √2*i =

               = √( [-4]^2 + [√2*i]^2 ) = √(16+2) = √18 = 3√2