Answer:
The general formula for the total surface area of a regular pyramid is T. S. A. =12pl+B where p represents the perimeter of the base, l the slant height and B the area of the base.
Answer:
that is the solution to the question
Answer:
56
Step-by-step explanation:
Answer:
h(2) = 7/4
h(-3) = -2
h(-2) = 11/(-8)
h(-3) - h(-2) = -(5/8)
Step-by-step explanation:
h(x) = (2x^2-x+1) / (3x-2)
h(2) = (2*2^2 - 2 + 1) / (3*2 - 2)
= (8 - 2 + 1) / (6 - 2)
= 7/4
h(-3) = {2*(-3)^2 - (-3) + 1} / {3*(-3) - 2}
= (18 + 3 + 1) / (-9 - 2)
= 22/(-11)
= -2
h(-2) = {2*(-2)^2 - (-2) + 1} / {3*(-2) - 2}
= (8 + 2 + 1) / (-6 - 2)
= 11/(-8)
h(-3) - h(-2) = (-2) - {11/(-8)}
= -(5/8)
Hope this will help. Please give me brainliest.
Answer:
-1
Step-by-step explanation:
This all comes down to the substitution. I am assuming that (4x2) is meant to be 4x^2 so I will solve as that.
4(-2)^2 = 4(4) = 16
4(-2) = - 8
-2(3)^2 = -2(9) = -18
3(3) = 9
16-8-18+9= -1
