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blondinia [14]
3 years ago
14

Divide (12n^3+8n^2-6n)/2n^2

Mathematics
1 answer:
nexus9112 [7]3 years ago
8 0
\frac{12n^{3} + 8n^{2} - 6n}{2n^{2}} = \frac{12n^{3}}{2n^{2}} + \frac{8n^{2}}{2n^{2}} - \frac{6n}{2n^{2}} = 6n + 4 - \frac{3}{n}
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Answer:

(0,5)

Step-by-step explanation:

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3 years ago
The red thing at the top is a right angle. Find the missing side lengths and leave answers as radicals in simplest form ILL GIVE
atroni [7]

Answer:

A. x = 13

y = (13√3)/3

Step-by-step explanation:

Reference angle = 30°

Hypotenuse = (26√3)/3

Adjacent = x

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✔️Apply CAH to find x:

Cos 30 = Adj/Hyp

Cos 30 = x/(26√3)/3

√3/2 = x*3/(26√3) (cos 30 = √3/2)

√3/2 = 3x/(26√3)

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6x = 26*3

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x = 78/6

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✔️Apply SOH to find y:

Sin 30 = Opp/Hyp

Sin 30 = y/(26√3)/3

Sin 30 = y*3/(26√3)

½ = 3y/(26√3) (sin 30 = ½)

Cross multiply

2*3y = (26√3)*1

6y = 26√3

Divide both sides by 6

y = (26√3)/6

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5 0
3 years ago
WILL GIVE BRAINLIEST|<br><br><br> Beginning in 2011, Yemen was drawn into a civil war because of:
Lady bird [3.3K]

Answer:

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2 years ago
15*x+12+10-20=12<br><br><br> WHAT
kupik [55]

Answer:

Step-by-step explanation:

15x + 12 + 10 - 20 = 12

15x + 22 - 20 = 12

15x + 2 = 12

15x = 12 - 2

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3 0
4 years ago
Read 2 more answers
1) Jo Anne needs to do a speech in her English class that can't be more than 4 minutes
djyliett [7]

Answer:

( 0 < y < 23 / 6 ) mins

Step-by-step explanation:

Solution:-

We will define a variable ( x ) as the time it took for Jo Anne to give her speech at home.

The time taken to give her speech must always be less than 4 minutes. We can express this mathematically using an inequality as follows:

                              ( 0 < x < 4 ) minutes

Jo Anne gave her speech which was 10 seconds less than the one she practised at home. We will convert the time in seconds to minutes as follows:

                             10 s * \frac{min}{60 s}  = \frac{1}{6} min

The time taken by Jo Anne to complete her speech in English class can be represented as:

                             y = x - 1/6

Using the range of time that Jo Anne could take in delivering her speech in the class would be:

                                    0 < x < 4

                            0 - 1/6 < y < 4 - 1/6

                            -1/6 < y < 23 / 6

Since time can not be less than zero. We correct the lower limit to " 0 " as follows:

                              ( 0 < y < 23 / 6 ) mins

   

7 0
4 years ago
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