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natka813 [3]
3 years ago
5

Please please please help!

Mathematics
1 answer:
Alenkinab [10]3 years ago
7 0

Answer:

h=A-πr²÷2πr

Step-by-step explanation:

M making h subject

A=2πrh+πr²

A-πr²=2πrh

A-πr²÷2πr=h

h=A-πr²÷2πr

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To inscribe a circle in the attached triangle, we must follow the following steps. The resultant figure is the first one below.

1. Draw the angle bisector of angle JKL. The straight line in the green one.

2. Draw the angle bisector of angle KLJ. The straight line in the blue one.

3. Draw point D at these two lines.

4. Draw a line through point D perpendicular to side JK. The straight line in the red one.

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To circumscribe a circle in the attached triangle, we must follow the following steps:

1. Draw the perpendicular bisector of the side FG. The straight line in the red one. The resultant figure is the second one below.

2. Draw the perpendicular bisector of the side GH. The straight line in the blue one.

3. The center of the circle is the intersection of these two lines

4. Draw a circle with center at D (point of concurrency).

<h3>3. Construct the two lines tangents to circle</h3>

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3 years ago
Assume that the weights of quarters are normally distributed with a mean of 5.67 g and a standard deviation of 0.07 g. If a vend
Black_prince [1.1K]

Answer:

0.98046

Step-by-step explanation:

Given:

  • μ = 5.67
  • σ = 0.07

Here we are required to find

P(5.48 <X<5.82) and between 5.48 and 5.82 we each z-score given by

<em>z = (x - μ) / σ</em>

So 5.48 we have z = -2.714  and 5.82 we have  z = 2.143

Therefore we have the area of interest on the normal distribution chart given by :

P( -2,714 < z < 2.143)

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= 1 - 0.01954 = 0.98046

6 0
3 years ago
Read 2 more answers
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