You have the intercepts and x-coordinate of the vertex correct. There appears to be a math error in the calculation of the y-value of the vertex.
f(7/8) = (4*7/8 -7)*(7/8) -15 = -49/16 -15 = -289/16 = -18.0625
Answer:
45 sq yd
Step-by-step explanation:
area of square: 8*6= 48
area to triangle: 2*3/2 = 3
48 - 3 = 45
Putting the value , so g = 15/2-3/2 = 12/2 = 6
so the answer is A !!
Answer:
a). Area of the parallelogram = 8 cm²
b). Area of both the triangles = 4 cm²
Step-by-step explanation:
a). Area of the given parallelogram ABCD = Base × Height
= DC × (Vertical distance between
AB and DC)
= 9 × 
= 8 ft²
b). If we decompose this parallelogram into two triangles ΔABC and ADC by a diagonal AC,
Area of both the triangles will be equal.
(Since, diagonal of a parallelogram divides the parallelogram into two equal triangles)
Therefore, area of ΔABC = Area of ΔADC = 4 ft²
Answer:
no it cannot
Step-by-step explanation:
becuase of many reasons
