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3 years ago

What is 63,020,000 in scientific notation?

Mathematics

2 answers:

Makovka662 [10]3 years ago

7 0

The answer is 6.302 x 10^7

Marina86 [1]3 years ago

4 0

Answer:

the answer is 10 times 10 to the 7th power

Step-by-step explanation:

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Differentiate the function. f(x) = ln(25 sin^2(x))

tigry1 [53]

Use the chain rule.
Let u = 25sin²(x), such that dy/dx = dy/du · du/dx

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$\frac{dy}{dx} = \frac{2cos(x) sin(x)}{sin^{2}(x)}$

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3 years ago

11 + 11 = 4 22 + 22 = 16 33 + 33 = ?

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Answer:

Step-by-step explanation:

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3 years ago

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seagull is flying at 125 feet above sea level. A dolphin is swimming 23 feet below sea level. What is the distance in feet betwe

hjlf

Answer:

102 feet.

Step-by-step explanation:

-23ft + 125ft = 102 ft

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3 years ago

Evaluate by using suitable property: (-343) x (-12) + (-343) x (-88) . Mention the property used.

Natalka [10]

Answer:

26,068

Step-by-step explanation:

(-343) x (-12) + (-343) x (-88)

= -4116 + 30,184

= 26,068

4 0

3 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

3 years ago