T represents hours, so if c(1.5)=c(t) as it mentioned in the problem, then 1.5 equals hours, and c represents cost, so if cost + time equals nine then I think it's a
First equation is: x - y = 12
x = 12 + y
Now, substitute this in 2nd equation,
2x - 3y = 27
2(12+y) - 3y = 27
24 + 2y - 3y = 27
-y = 27 - 24
y = -3
In short, Your Answer would be -3
Hope this helps!
Answer:

Step-by-step explanation:
The logistic equation is the following one:

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.
In this problem, we have that:
Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that
.
The number of fish tripled in the first year. This means that
.
Using the equation for P(1), that is, P(t) when
, we find the value of r.









Applying ln to both sides.


This means that the expression for the size of the population after t years is:

Rewrite the fractions with common denominators and then answer:
A:
13/14 > 25/28
26/28 > 25/28
This is True
B) 21/45 < 20/45 False
C) 10/12 > 11/12
False
D) 20/25 < 8/25
False
The true statement is A.