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3 years ago

A circle has a diameter of 8 m.

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

6 0

The answer is B. The formula for circumference is 2piR or just the diameter times pi

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Can someone help me please id really appreciate it , i’ll give you brainliest

ozzi

Answer:

Alternate Exterior Angles Theorem

Step-by-step explanation:

By looking, we can see that they are exterior angles. Because 2 parallel lines are cut by a transversal, the angles are congruent.

4 0

3 years ago

Is this a function why or why not?

Naily [24]

Yes, it is a function because each input has only one output.

Hope it helps!

6 0

3 years ago

1.) Expand and simplify (6x-7)+(x-3)+(4x-5) * a.)11x-5 b.)11x-15 c.)10x-15 d.)10×1

LiRa [457]

Answer:

the answer is b 11x-15

Step-by-step explanation:

your collecting like terms then combining them

7 0

4 years ago

Use function notation to write the equation of the line

blondinia [14]

$f(x)=mx+b\to y=mx+b$

We have two points:

$(-3,\ 0);\ (-4,\ 7)$

The point slope form of the line:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

Substitute

$m=\dfrac{7-0}{-4-(-3)}=\dfrac{7}{-1}=-7$

$y-0=-7(x-(-3))\\\\y=-7(x+3)\\\\y=-7x-21$

Answer:

$f(x)=-7x-21$

8 0

3 years ago

Please help !!! I can’t solve this The teacher doesn’t teach well

Scorpion4ik [409]

So here are 4 rules when it comes to exponents:

When you raise a power to a power, you really just multiply the exponents: $(x^m)^n=x^{m*n}$
When you multiply 2 exponents of the same base, you add the exponents together: $x^m*x^n=x^{m+n}$
When you divide 2 exponents of the same base, you subtract the exponents: $\frac{x^m}{x^n}=x^{m-n}$
To convert a negative exponent into a positive one, flip it to its reciprocal: $x^{-m}=\frac{1}{x^m}\\ \frac{1}{x^{-m}}=\frac{x^{m}}{1}=x^m$

Part A:

$\frac{2x^3y^3}{4y^2}=\frac{1}{2}x^{3-0}y^{3-2}=\frac{1}{2}x^3y$

Part B:

$(\frac{x^{-8}}{y^{11}})^{-2}=\frac{x^{-8*-2}}{y^{11*-2}}=\frac{x^{16}}{y^{-22}}=\frac{x^{16}y^{22}}{1}=x^{16}y^{22}$

Part C:

$\frac{(2x^3)(x^4)^2}{8x^{11}}=\frac{(2x^3)(x^{4*2})}{8x^{11}}=\frac{(2x^3)(x^8)}{8x^{11}}=\frac{2x^{3+8}}{8x^{11}}=\frac{2x^{11}}{8x^{11}}=\frac{1}{4}x^{11-11}=\frac{1}{4}x^0=\frac{1}{4}$

5 0

3 years ago