32. how do you convert 15 meters to millimeters?

Between which two square roots of integers could you find 2.7182818284

horsena [70]

Well 2.7182818284 is from euler's constant e.

Integers are whole numbers positive and negative. since 2.7182818284 is positive (and you can't take square root of negative number) the integers we find will be positive.

List out square roots.
sqrt1 = 1
sqrt 2 = 1.41
sqrt 3 = 1.73
sqrt 4 = 2
sqrt 5 = 2.2
sqrt 6 = 2.4
sqrt 7 = 2.6
sqrt 8 = 2.8 -----> this is over the constant.

so it's between the square root of 7 and 8

6 0

3 years ago

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What is true about all cylinders

Natalija [7]

It is round and has a circle on the top and bottom.

8 0

4 years ago

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PLEASE HELP ASAD

irinina [24]

Answer:

Multiply g by 23 to get

the missing value in the last row is 92.

A real-world situation that is represented in the table is “Rio’s car gets 23 miles per gallon.”.

or A,D,E

6 0

3 years ago

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Which set of equations would have infinite solutions?

vaieri [72.5K]

The answer is b the two equations are equal to each other

4 0

3 years ago

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I need help please, I am so confused.

vazorg [7]

Answer:

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

Therefore, to find the x-intercepts, substitute y = 0 and solve for x.

The vertex is the turning point: the minimum point of a parabola that opens upward, and the maximum point of the parabola that opens downward. As a parabola is symmetrical, the x-coordinate of the vertex is the midpoint of the x-intercepts.

Equation: $y=x(x-2)$

$\implies x(x-2)=0$

$\implies x=0$

$\implies (x-2)=0 \implies x=2$

Therefore, the x-intercepts are x = 0 and x = 2

The midpoint of the x-intercepts is x = 1, so the x-coordinate of the vertex is x = 1

Equation: $y=(x-4)(x+5)$

$\implies (x-4)(x+5)=0$

$\implies (x-4)=0 \implies x=4$

$\implies (x+5)=0 \implies x=-5$

Therefore, the x-intercepts are x = -5 and x = 4

The midpoint of the x-intercepts is x = -0.5, so the x-coordinate of the vertex is x = -0.5

Equation: $y=-5x(3-x)$

$\implies -5x(3-x)=0$

$\implies -5x=0 \implies x=0$

$\implies (3-x)=0 \implies x=3$

Therefore, the x-intercepts are x = 0 and x = 3

The midpoint of the x-intercepts is x = 1.5, so the x-coordinate of the vertex is x = 1.5

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

4 0

2 years ago