Answer: 1/5, 1/2, 0.
Step-by-step explanation:
given data:
no of cameras = 6
no of cameras defective = 3
no of cameras selected = 2
Let p(t):=P(X=t)
p(2)=m/n,
m=binomial(3,2)=3!/2!= 3
n=binomial(6,2)=6!/2!/4! = 15
p(3)= 3/15
= 1/5.
p(1)=m/n,
m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5
n=binomial(6,2)= 15
p(2)= 7.5/15
= 1/2
p(0)=m/n,
m=0
p(0)=0
$1.50
I hope this is what you need
Answer:
Option B.
Step-by-step explanation:
Remember that the profit is defined as the difference between the revenue and the cost.
So, having a profit y = 0 means that the woodworker did not win nor lose anything.
Then the zeros of the function, the values of x such that the graph intersects the x-axis, are the prices such that she does not win nor loss anything.
In the graph we can see that the zeros are at:
x = 15 (the first one)
x = 70 (the second one)
so the zeros are at x = 15 and x = 70, and these are the prices such that the profit is zero, so at these prices she does not make nor lose money.
The correct option is B.
1 reflection, 2 rotation,
