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Darya [45]
3 years ago
9

What happens to the value of the expression 80/h as h increases from a small positive number to a large positive number?

Mathematics
2 answers:
Alex787 [66]3 years ago
6 0

Answer:

The numerator decreases when the denominator increases

Step-by-step explanation:

STatiana [176]3 years ago
4 0

For this case we have the following expression:

\frac {80} {h}

We substitute a small number h, that is, h = 0.05

So:

\frac {80} {0.05} = 1600

It is observed that the value of the expression is very large, that is, it increases with small values of h

We substitute a large number h, that is, h = 500

So:

\frac {80} {500} = 0.16

It is observed that the value of the expression decreases.

Answer:

The value of the given expression decreases when h increases from a small positive number to a large positive number.

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When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, should the signs in the binom
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When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, the signs in the binomials should be both positive

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the true statement?</h3>

The form of the polynomial is given as:

ax2 + bx + c

Where a, b, and c are positive real numbers.

Since a, b, and c are positive real numbers. then the form of the expansion would be:

ax2 + bx + c = (dx + e)(fx + g)

<h3>Example to verify the claim</h3>

Take for instance, we have the following quadratic equation

x^2 + 6x +  8

Expand the equation

x^2 + 6x +  8 = x^2 + 4x + 2x +  8

Factorize the equation

x^2 + 6x +  8 = (x + 2)(x + 4)


Hence, the signs in the binomials should be both positive

Read more about polynomials at:

brainly.com/question/4142886

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In a call center that stays open all the time, calls arrive as a poisson process with a mean rate of 0.3 complaints per hour.(a)
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The probability the 51st call arriaves within 150hours is 0.0431, the probability the next call arrives within the next 2 hours 0.5488, the probability the sum of these 50 numbers is less than 356 is 0.4165.

Data;

  • Mean rate = 0.3
  • x = 50
  • standard deviation = ?

<h3>Poission Rule</h3>

Using poission formula,

P(x=x) = \frac{e^-^\lambda - \lambda^x}{x!}\\\lambda = 0.3 per minute

Let's substitute the values into the formula.

For 50 calls in 150 hours

For 150 hours = x = 0.3 * 150 = 45

p(x=50) = \frac{e^-^4^5 * 45^5^0}{50!} = 0.0431

b)

The probability the next call arrives after 2 hours.

\lambda = 0.3 * 2 = 0.6\\p(x=0) = \frac{e^-^0^.^6 * 0.6^0}{0!} = 0.5488

c)

The number of calls recieved each day is recorded for 50 consecutive days.

for 50 days;

\lambda = 0.3 * 50 * 24 = 360

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The standard deviation is given as

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The probability the sum of these 50 number is less than 356 is

p = (x < 356) = z = \frac{356 - 360}{18.974} = -0.2108\\p(z < -0.2108) = 0.4165

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