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Amanda [17]
3 years ago
14

72 is 75 percent of what number

Mathematics
2 answers:
aniked [119]3 years ago
3 0
Its ans will become 96
Vlad [161]3 years ago
3 0
96 IS THE ANSWER whoops caps
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PLEASE HELP ME ON THESE PROBLEMS, ITS URGENT! (Help for any of these would be greatly appreciated!)
Anvisha [2.4K]
1.) We can solve the problem by developing a linear model.
Let x represent the quantity to be used of the grade of coffee that sells for $70 per pound, and y represent the quantity to be used of the grade of coffee that sells for $80 per pound, then
\left\begin{array}{c}x+y=80 . . . (1)\\70x+80y=76(80) . . . (2)\end{array}\right  \\   \\ \Rightarrow  \left\begin{array}{c}80x+80y=6400 . . . (3)\\70x+80y=6080 . . . (4)\end{array}\right  \\  \\ \Rightarrow10x=320 \\  \\ \Rightarrow x=32 \\  \\ \Rightarrow y=80-32=48
Therefore, 32 pounds of the grade of coffee that sells for $70 per pound, and 48 pounds of the grade of coffee that sells for $80 per pound should be used.


2.) Volume of alcohol in the original mixture
\frac{35}{100} \times 40=14 quarts

Let x be the number of quarts of alcohol to be added, then
Volume of alcohol in the new mixture
\frac{48}{100} \times (40+x)=14+x \\  \\ \Rightarrow19.2+0.48x=14+x \\  \\ \Rightarrow0.52x=5.2 \\  \\ \Rightarrow x=10

Therefore, 10 quarts of pure alcohol should be added


3.) Original proportion of white paint in the mixture
=\frac{5}{5+11}=\frac{5}{16}

Let x be the number of gallons of white paint to be added, then
\frac{5+x}{16+x}=\frac{2}{3} \\  \\ \Rightarrow3(5+x)=2(16+x) \\  \\ \Rightarrow15+3x=32+2x \\  \\ \Rightarrow x=32-15=17
Therefore, 17 gallons of white paint should be added.


4a.) Let the three consecutive odd integers be x - 2, x and x + 2, then
x - 2 + x + x + 2 = 25 \\  \\ \Rightarrow3x=25\Rightarrow x=8.33
which is not an integer.
Hence, the sum of three consecutive odd integers cannot be 25.

4b.) Let the three consecutive odd integers be x - 2, x and x + 2, then
x - 2 + x + x + 2 = 45 \\ \\ \Rightarrow3x=45\Rightarrow x=15
Thus, the three consecutive odd intergers whose sum is 45 are 13, 15 and 17.


5.) If all pipes are open and the tank was initially empty, let t be the time it will take to fill the tank, then
\frac{1}{t} = \frac{1}{9} + \frac{1}{12} - \frac{1}{15} = \frac{20+15-12}{180} = \frac{23}{180} \\  \\ \Rightarrow t= \frac{180}{23} =7.83
Therefore, it will take 7.83 hours to get the tank filled up.
3 0
3 years ago
Find the equation of the line with slope m=1/4 that contains the point (4,5).
sladkih [1.3K]

Answer: x - 4y = -16

Step-by-step explanation: Since we're given a point and a slope, we can write the equation of this line using the point-slope formula.

<h2>y  -  y₁  =  m(x  -  x₁)</h2><h2 />

The given point, (4, 5), represents (x₁, y₁).

So if we plug all our given information into the formula,

including our slope of 1/4, we get y - 5 = 1/4(x - 4).

To put our equation in standard form, first, distribute

the 1/4 through the parentheses.

So we get y - 5 = 1/4x - 1.

Remember that standard form cannot have any fractions in it so our next step is to multiply both sides of the equation by 4 to get rid of the fraction.

That gives us 4y - 20 = x - 4.

Now moves the -20 to the right side by adding 20 to both sides.

So we get 4y = x + 16.

Now subtract x from both sides to get -x + 4y = 16.

Finally, our coefficient on our x term must be positive so we

divide both sides by -1 to get x - 4y = -16.

7 0
3 years ago
-12 -24 which one is greater or less than​
Simora [160]

Answer:

-12 > -24

Step-by-step explanation:

When the numbers are negative the number that is closer to zero is the greatest

7 0
3 years ago
Read 2 more answers
Select the correct answer.<br> Find the value of x.<br> Please answer!!!
olga nikolaevna [1]

C. 64

Rewrite the logarithm:

8=x^.5

Solve by raising both sides of the equation to the power of the inverse (in this case, the inverse of .5, which is 2):

8^2=x^(.5*2)

64=x

6 0
3 years ago
Help please I really really need this is my last question help hurry
den301095 [7]
1/6 is the answer. Good luck!
4 0
3 years ago
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