Answer:
14 quarters and 28 nickels
Step-by-step explanation:
System of Equations where x = number of quarters and y = number of nickels
(1) equation with value of each coin
0.25(x)+0.05(y) = 4.90
(2) total number of coins
x + y = 42
Solve system of equations using either substitution or elimination
(elimination multiplying equation 2 by -0.5)
.25(x) + 0.05(y) = 4.90
-0.05(x) - 0.05(y) = 42 * (-0.05)
(3) Resulting equation
.20(x) = 2.8
x = 14
plug x into equation 2
14 + y = 42
y = 28
There are 14 quarters and 28 nickels in Mary's collection.
Answer:
6
Step-by-step explanation:
3(1)=3 3(2)=6 3(3)=9 3(4)=12 3(5)=15
3(6)=18 3(7)=21 3(8)=24
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3(6)=18 is closest to 20
so the greatest number of batches Xiaoming can make is 6.
Step-by-step explanation:
-2/3f =9.2
cross multiply
27,6= -2f
divide both sides by 2
f = - 13.8
-1/8n = -2/7
cross multiply
-16 = -7n
divide
n = 2.29
12/20n = -36/44
cross multiply
528 = - 720n
divide
n= -0.733
-64.5g = -25.8
divide both sides by -64.5
g = -0.4
the last one has no variable
Answer:
see attached
Step-by-step explanation:
Here's your worksheet with the blanks filled.
__
Of course, you know these log relations:
log(a^b) = b·log(a) . . . . . power property
log(a/b) = log(a) -log(b) . . . . . quotient property
log(x) = log(y) ⇔ x = y . . . . . . . . . equality property
Answer:
5, 10, 15, 20, 25, 30, 35, 40, 45, 50, ... 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, ... 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, ...
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Hope this helps
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