Answer:
The zeros are x1=4.45 and x2=-0.45.
x1 is between 4 and 5.
x2 is between -1 and 0.
Step-by-step explanation:
We have the function:

As this is a quadratic function, we can calculate the zeros of the function with the quadratic equation:

The zeros are x1=4.45 and x2=-0.45.
x1 is between 4 and 5.
x2 is between -1 and 0.
Answer:
D I'm sure....................... :D
Solve the equation and it will add up to -6 so
3×-7=-21
-21-10=-31
-31+25=-6
128 = a + + 4(a + 10) + (a + 10)
128 = a + 4a + 40 + a + 10
128 = 6a + 50
128-50 = 6a
78 = 6a
13 = a
1st = a = 13
2nd = 4(a + 10) = 4(23) = 92
3rd = a + 10 = 23