Answer:
let the two number be x and y then,
x+y=12
x-y=-4
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2x=8
or, x = 4 put the value of x in first equation
4+y= 12
or, y=12-4
or, y= 8 hence the two number is 4 and 8
Answer:
The answer to the question is;
The number of papers expected to be handed in before receiving each possible grade at least once is 14.93.
Step-by-step explanation:
To solve the question , we note that it is a geometric distribution question which have equal probabilities and therefore is a form of Binomial distribution with Bernoulli trials, where we are conducting the trials till we have r successes
Since we have r = 6, we will have to find the expected value of the number of trials till the nth paper handed in receives a previously awarded grade.
We therefore have,
The Probability that out of six papers turned 5 are different scores is given by
P(Y=5) = p'= q⁵p = (1-p)⁵p = 3125/46656
Therefore p' = the probability of receiving different grades once then the expected value is given by
E(X) = 1/p' = 46656/3125 = 14.93.
N= 12
Subtract 70.85 and 7.25 which equals 63.6. Then take 63.6 divided by 5.3 and it equals 12! Hope this helps.
The place value of 1 is hundred thousands.
Answer:
The green would take 4 and the blue would take 16 times respectivly. I did it by finding the volumes of the cups in terms of pi, then dividing it by the volume of the sink.
Step-by-step explanation:
So the volume of the whole half sphere is 512pi.
Now we have to find the volumes of the cup.
Equation: 
Blue cup:
It would take 16 times to drain it completly.
Green cup:
It would take 4 times to drain it completly.
