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ivolga24 [154]
3 years ago
5

Restrictions on the quantity of goods that can enter a country

Business
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer:

Quota;

Explanation:

To protect local manufacturers from unfair competition from foreign goods,  governments restrict the quantities of imports. Imposing these restrictions is the application of a quota policy.

Quota places a limit on the maximum quantity of a particular product that business people can import. Quota aims to enable domestic producers to manufacture and sell their products in the country at reasonable prices. Increased domestic production creates employment and stimulates economic developments in the country.

Quota may also be used to regulate the volume of trade between a country and its trading partners.

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Accountants truly represent the financial managers of a business. true false
Alex73 [517]
False. Accountants crunch the numbers and report to financial managers who make the decisions. 
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Mostert Music Company had the following transaction inMarch:a. Sold instruments to customers for $10,000; received$ 6,000 in cas
devlian [24]

Answer: The answer is given below

Explanation:

It should be noted that for the cash basis income statement, the revenue were cash sales of $6000 and customer deposit of $1000 making a total of $7000. The expenses were the inventory purchased of $1000 and the wages paid of $600 making $1600. Cash income was now:

= $7,000 - $1600

= $5400

For the accrual income statement, the revenue was $10000 and expenses were $7800. The cash Income was now: $10,000 - $7800 = $2,200

Check the attachment for further clarification.

3 0
3 years ago
Support agents at Universal Containers research solutions to customer issues by asking various subject matter experts (SMEs) at
Sholpan [36]

Answer:

A,C,D

Explanation:

Remember, we are told the issue concerns "support agents" working for a company–Universal Containers. Thus, they will be using Salesforce inorder to document their findings.

i. Case feed is one useful feature that quickly allows the support agents to edit, store and change the status of cases where necessary.

Ii. Case group is another useful feature to group cases that the support agents consider as been interrelated.

iii. Case comments feature allows them to read through case by case comment from the participants in the research, allowing proper insight into minds of the customers.

6 0
4 years ago
Pressure with Two Liquids, Hg and Water. An open test tube at 293 K is filled at the bottom with 12.1 cm of Hg, and 5.6 cm of wa
Radda [10]

Answer:

1170839.28 dyn/cm^2

16.9816 psia

117.083928 kN/m^2

Explanation:

To calculate the absolute pressure in the bottom of tube we need to sum the atmosferic and gauge pressure.

P_{abs}=P_{atm}+P_G

And the gauge pressure is given by the contributions of columns of water (P_{w}) and mercury(P_{Hg}), we can calculate the contribution of each column as:

P= \rho g h (*)

where \rho is the respective density, g gravity and h is height.

So we have all the data required to use the above equations (P_{atm}, height and density of each column) we only need to be carefully with the units.

For simplicity we can to express all pressure contributions in mmHg ( P_{atm}, P_{w} and P_{Hg}). Note that the units "x" mmHg  means the pressure at the bottom of a column of mercury of "x" mm high. For example, in this case we have a column 12.1 cm of Hg, that is a column of 121 mmHg (passing from cm to mm only requires multiply by 10) pressure exerted by that column is 121 mmHg.

Now pressure of 5.6 cm (56 mm) of water would be 56 mm of water, but it is not the same that mmHg, since the density of water is lower, the pressure exerted by 1 mm of water is lower than the exerted by 1 mm of Hg. The conversion between mmHg and mm of water is given by the relation between the densities.

mmHg=\frac{\rho_w*mmH_2O}{\rho_{Hg}}

mmHg=\frac{0.998*mmH_2O}{13.55}=0.0737 mmH_2O

And pressure of water in mmHg is

0.0737*56=4.1246 mmHg

The absolute pressure is:

P_{abs}=P_{atm}+P_G= 756 + 121 + 4.1246  = 881.1246 mmHg = 88.11246cmHg

To pass to dyn/cm^2 units we need to use the equation (*)

P= \rho g h = 13.55 \frac{g}{cm^3} * 980.665 \frac{cm}{s^2} * 88.11246 cmHg = 1170839.28 \frac{g}{cm s^2} = 1170839.28 \frac{dyn}{cm^2}

Note: We need to use cm Hg for units coherence

Now passing from dyn/cm^2 to kN/m^2 (or kPa) we need to consider that 1 dyn is 10^{-8} kN and 1 cm^2 is 10^{-4} m^2.  

1170839.28 \frac{dyn}{cm^2} * \frac{10^{-8}kN}{1 dyn}*\frac{cm^2}{10^{-4}m^2}=117.083928kN/m^2

Now passing kN/m^2 to psia. We need to consider that 1 psia is 6.89476.

117.083928kN/m^2*\frac{1psia}{6.89476kN/m^2}=16.9816 psia

 

8 0
3 years ago
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