Question

GEOMETRY: Help ASAP! Show all work. Incomplete or off-topic answers will be reported.

Answer 1

midpoint of (x1,y1) and (x2,y2) is $(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}$

so if midpoint is (-3,2) and one point is (0,11) then

$(-3,2)=(\frac{0+x_2}{2}, \frac{11+y_2}{2})$

$-3=\frac{x_2}{2}$

$-6=x_2$

$2=\frac{11+y_2}{2}$

$4=11+y_2$

$-7=y_2$

the coordinates of k is (-6,-7)

circumference=2*pi*r

area=pi*r^2

if r=3 then

circumference=2*pi*3=6pi in

area=pi*3^2=pi*3*3=9pi in²