Answer:
and 
Step-by-step explanation:
The equation of curve is

We need to find the equation of the tangent line to the curve at the point (-3, 1).
Differentiate with respect to x.
![2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})](https://tex.z-dn.net/?f=2%5B2%28x%5E2%2By%5E2%29%5Cfrac%7Bd%7D%7Bdx%7D%28x%5E2%2By%5E2%29%5D%3D25%282x-2y%5Cfrac%7Bdy%7D%7Bdx%7D%29)

The point of tangency is (-3,1). It means the slope of tangent is
.
Substitute x=-3 and y=1 in the above equation.





Divide both sides by 130.

If a line passes through a points
with slope m, then the point slope form of the line is

The slope of tangent line is
and it passes through the point (-3,1). So, the equation of tangent is


Add 1 on both sides.


Therefore,
and
.
nothing can be further simplify in this problem
Explanation is in a file
bit.
ly/3a8Nt8n
You have a special type of function, so you have to express the domain and range of each interval. Every aspect of this graph is closed, so you will only use brackets when writing your answers. Hence, you get [30,5] for the first interval, since there is a horizontal distance of 30 and a vertical distance of 5. You repeat the same process for each interval.
The formula for the amount A in an account with principal P and interest rate r compounded annually for t years is
... A(t) = P(1+r)^t
You want to find A when P=400, r=0.05, and t=3. Substituting those values gives you
... A(3) = 400·(1 +0.05)³
The appropriate choice is
... A. A(3) = 400·(1 +0.05)³