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matrenka [14]
4 years ago
11

I need help with problem 27,28,29

Mathematics
2 answers:
Grace [21]4 years ago
7 0
Can't see 28 and 29 plz take a better picture
Rom4ik [11]4 years ago
5 0
27 has to be C
I can't see the whole question for 28 and 29
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I'm very confused on how to even figure out the question and what I'm supposed to do
Tasya [4]

Answer:

To solve a system of linear equations graphically we graph both equations in the same coordinate system. The solution to the system will be in the point where the two lines intersect. The two lines intersect in (-3, -4) which is the solution to this system of equations. I hope this helped!

5 0
2 years ago
Ay anyone willing to help me with my work kinda lost
kirill115 [55]

Okaayyy

Set B has the greater mode

7 0
3 years ago
I rlly need help!!!!!!!
Yuliya22 [10]
The correct answer is the 2nd one
3 0
3 years ago
Please help! What is the line's slope??
MariettaO [177]
The slope is the rise over run. Basically, any line has a constant increase. If you are looking at a line on a graph and each point it meets at is 1 up and 1 over, the slope is 1. Say the line goes up two and over one for each time it meets an actual point, the slope would be 2. If it is 1 up and 2 over, it would be 1/2.
4 0
3 years ago
Answer for number 12
aalyn [17]

Answer:

12 a. 4605 feet 12 b. 1,459,063 square feet

Step-by-step explanation:

For the perimeter, we simply add the lengths of each of the 5 sides together (or multiply 5 times one side length).

P = 5(921)

P = 4605 feet

For the area, we will use composition...add the area of the triangle to the area of the trapezoid.

For the area of the triangle, the formula is

A=\frac{1}{2}bh.

Filling in our values gives us

A=\frac{1}{2}(1490)(541) and

A = 403,045 square feet.

Now for the trapezoid.  The formula for a trapezoid is

A=\frac{1}{2}(b_{1}+b_{2})(h)

where the b's represent the bases and the h represents the height.  Filling in our values gives us

A=\frac{1}{2}(921+1490)(876)

Work inside the parenthesis first:

A=\frac{1}{2}(2411)(876) and

A = 1,056,018

Now we add those together to get that area of the Pentagon is 1,459,063 square feet

4 0
3 years ago
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