The domain is the set of x-values of a function. The range is the set of y-values of a function.
You are told that the domain, or x-values, are -8, -6, -3, -2, and 2. To find the range, you just need to plug in each of the x-values into the function <span>y = -3x + 7 and find the value of y.
1) When x = -8:
</span><span>y = -3x + 7
y = -3(-8) + 7
y = 24 + 7
y = 31
2) When x = -6
</span>y = -3x + 7
y = -3(-6) + 7
y = 18 + 7
y = 25
3) When x = -3
y = -3x + 7
y = -3(-3) + 7
y = 9 + 7
y = 16
4) When x = -2
y = -3x + 7
y = -3(-2) + 7
y = 6 + 7
y = 13
5) When y = 2
y = -3x + 7
y = -3(2) + 7
y = -6 + 7
y = 1
The range is {31, 25, 16, 13, 1}.
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Answer: {31, 25, 16, 13, 1}
Answer:
10 you just add them and or count down
Answer:
∠RPQ = 27
Step-by-step explanation:
In ΔSRQ,
∠R = 90
∠SQR = 36°
∠R + ∠SQR + ∠RSQ = 180 {Angle sum property of triangle}
90 + 36 + ∠RSQ = 180
126 + ∠RSQ = 180
∠RSQ = 180 - 126
∠RSQ = 54°
∠PSQ +∠RSQ = 180 {Linear pair}
∠PSQ + 54 = 180
∠PSQ = 180 - 54
∠PSQ = 126
In ΔPSQ,
SQ = PS ,
So, ∠SQP = ∠SPQ {Angles opposite to equal sides are equal}
∠SQP = ∠SPQ =x
∠PSQ + x +x = 180 {Angle sum property of triangle}
126 + 2x = 180
2x = 180 - 126
2x = 54
x = 54/2
x = 27
∠RPQ = 27°
Answer:
y = -x + 2
Step-by-step explanation:
The desired equation must have the form y = mx + b.
Start with -2Y - 2X = -6 and solve for y: y + x = 2
Now solve this result for y:
y = -x + 2
