(2x+3y)+(7x-3y) First, group like terms together, so (2x+7x) + (3y-3y). Then simplify within the parentheses. 2x+7x = 9x and 3y-3y = 0, so you have 9x, which cannot be simplified any further. The answer is 9x.

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3 years ago

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CON PROCESOS POR FAVOR

labwork [276]

Answer:

$\dfrac{149}{40}$

$\dfrac{38}{15}$

Step-by-step explanation:

$(\dfrac{7}{8} + \dfrac{4}{5}) - (\dfrac{9}{20} + \dfrac{-5}{2}) =$

$= (\dfrac{7}{8} \times \dfrac{5}{5} + \dfrac{4}{5} \times \dfrac{8}{8}) - (\dfrac{9}{20} + \dfrac{-5}{2} \times \dfrac{10}{10})$

$= (\dfrac{35}{40} + \dfrac{32}{40}) - (\dfrac{9}{20} + \dfrac{-50}{20})$

$= \dfrac{67}{40} - (-\dfrac{41}{20})$

$= \dfrac{67}{40} + \dfrac{41}{20} \times \dfrac{2}{2}$

$= \dfrac{67}{40} + \dfrac{82}{40}$

$= \dfrac{149}{40}$

$(-\dfrac{6}{4} + \dfrac{3}{2}) + (\dfrac{6}{5} + \dfrac{4}{3}) =$

$= (-\dfrac{3}{2} + \dfrac{3}{2})+ (\dfrac{6}{5} \times \dfrac{3}{3} + \dfrac{4}{3} \times \dfrac{5}{5})$

$= 0 + \dfrac{18}{15} + \dfrac{20}{15}$

$= \dfrac{38}{15}$

4 0

2 years ago