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4 years ago

The range for the given domain of the function f(x) =3x-6/x+4.5 is what

2 answers:

5 0

The domain is the input number values you can substitute into the equation.

The range is the output values how do they appear like, what is the nature of the numbers.

So for f(x) = 3x - 6/x + 4.5

You can input any real number value for x, except 0, because you can not divide by 0, that is the 6/0.

So the domain is x set of all real numbers except 0. R - {0}

So when we substitute any number into f(x) = 3x - 6/x + 4.5, what kind of numbers do we get?

We get Real numbers, 0 is included.

So the range for f(x) set of all real numbers.

Drupady [299]4 years ago

4 0

Try to use mathway its very helpful

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3 years ago

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em> $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

<em>Camera 2nd has to cover the maximum angle</em>, i.e. $78.70^\circ$ .

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4 years ago

i need to help write the equation in vertex form for the parabola with vertex at ( 2,-1) and y - intercept 5

densk [106]

Answer: y= 5/2(x-2)^2 - 1

Step-by-step explanation:

y=a(x-2)^2 - 5

5=a(0-2)^2 - 5

10=a(-2)^2

10=a4

a=10/4 or 5/2

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4 years ago