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eduard
3 years ago
6

HE SODA MACHINE

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer:

yes and no

Step-by-step explanation:

if a machine is work a lot lot LOT, then it might be jamed

or the teacher might have accidentally pressed blast and you might have not seen the buttons correctly

( also i am not a student of yours )

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The answer is C) 110 degrees
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3 years ago
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If XX is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases:
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Answer:

(a) The mean, variance and standard deviation of <em>X </em>are 1.60, 0.96 and 0.98 respectively.

(b) The mean, variance and standard deviation of <em>X </em>are 3.20, 0.64 and 0.80 respectively.

(c) The mean, variance and standard deviation of <em>X </em>are 1.50, 0.75 and 0.87 respectively.

(d) The mean, variance and standard deviation of <em>X </em>are 4.00, 0.80 and 0.89 respectively.

Step-by-step explanation:

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The mean, variance and standard deviation of <em>X</em> are:

\mu=np\\\sigma^{2}=np(1-p)\\\sigma=\sqrt{np(1-p)}

(a)

For <em>n</em> = 4 and <em>p</em> = 0.40 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=4\times0.40=1.60\\\sigma^{2}=np(1-p)=4\times0.40\times(1-0.40)=0.96\\\sigma=\sqrt{np(1-p)}=\sqrt{0.96}=0.98

Thus, the mean, variance and standard deviation of <em>X </em>are 1.60, 0.96 and 0.98 respectively.

(b)

For <em>n</em> = 4 and <em>p</em> = 0.80 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=4\times0.80=3.20\\\sigma^{2}=np(1-p)=4\times0.80\times(1-0.80)=0.64\\\sigma=\sqrt{np(1-p)}=\sqrt{0.64}=0.80

Thus, the mean, variance and standard deviation of <em>X </em>are 3.20, 0.64 and 0.80 respectively.

(c)

For <em>n</em> = 3 and <em>p</em> = 0.50 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=3\times0.50=1.50\\\sigma^{2}=np(1-p)=3\times0.50\times(1-0.50)=0.75\\\sigma=\sqrt{np(1-p)}=\sqrt{0.75}=0.87

Thus, the mean, variance and standard deviation of <em>X </em>are 1.50, 0.75 and 0.87 respectively.

(d)

For <em>n</em> = 5 and <em>p</em> = 0.80 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=5\times0.80=4.00\\\sigma^{2}=np(1-p)=5\times0.80\times(1-0.80)=0.80\\\sigma=\sqrt{np(1-p)}=\sqrt{0.80}=0.89

Thus, the mean, variance and standard deviation of <em>X </em>are 4.00, 0.80 and 0.89 respectively.

6 0
3 years ago
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Step-by-step explanation:

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5 0
3 years ago
The perimeter of a rectangle swimming pool is 160 feet. The length of the swimming pool is four times its width . Find the dimen
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Formula for Perimeter of Rectangle:

P = 2(L + W)

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160 = 2(L + W)

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<span>So we can plug in '4W' for 'L' in the first equation.</span>
<span>160 = 2(L + W)

160 = 2(4W + W)

Combine like terms:

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Now we can plug this back into any of the two equations to find the length.

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So the width is 16, and the length is 64.</span>
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