We let x and y be the number of Hobbies & Recreation and Soliloquies episodes that Steve subscribe. The system of linear equation that best represent the given above is,
x + y = 10
32x + 42y = 340
The values of x and y from the system are 8 and 2, respectively. Thus Steve subscribed to 8 Hobbies & Recreation and to 2 Soliloquies episodes.
This is a division problem.
You need to divide 3/5 by 5.
(3/5) / 5 = (3/5 / (5/1) = 3/5 * 1/5 = 3/25
How many models does the following set have? 5,5,5,7,8,12,12,12,150,150,150
Strike441 [17]
<h3>
Answer: 3 modes</h3>
The three modes are 5, 12, and 150 since they occur the most times and they tie one another in being the most frequent (each occurring 3 times).
Only the 7 and 8 occur once each, and aren't modes. Everything else is a mode. It's possible to have more than one mode and often we represent this as a set. So we'd say the mode is {5, 12, 150} where the order doesn't matter.
to change unit from feet to cm just divide the length value by 30.48......
Given Information:
Total cards = 108
Red cards = 25
yellow cards = 25
Blue cards = 25
Green cards = 25
Wild cards = 8
Required Information:
Probability that a hand will contain exactly two wild cards in a seven-hand game = ?
Answer:
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
Step-by-step explanation:
The required probability is given by
P = number of ways of interest/total number of ways
The total number of ways of dealing a seven-card hand is
₁₀₈C₇
We want to select exactly 2 wild cards and the total wild cards are 8 so the number of ways of this selection is
₈C₂
Since the game is seven-card hand, we have to get the number of ways to select remaining 5 cards out of (108 - 8 = 100) cards.
₁₀₀C₅
Therefore, the setup for this problem becomes
P = number of ways of interest/total number of ways
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
This is the required setup that we can type into our calculators to get the probability of exactly two wild cards in a seven-hand card game with 8 wild cards and 108 total cards.