X^2+6x+8=0
To write the above in the form of (x-p)^2=q we proceed as follows:
i] Re-write the expression:
x^2+6x=-8
ii] Calculate for the vale of c.
c=(b/2a)²
given that:
b=6, and a=1
thus
c=(6/2*1)^2=9
iii]
Add 9 on both sides of the equation from i
x^2+6x+9=-8+9
simplifying we get:
x^2+6x+9=1
factoring the LHS we get:
(x+3)(x+3)=1
(x+3)²=1
The above is in the form of:
(x-p)²=q
where:
p=3 and q=1
<span> Perimeter <em>p</em> means adding up the four sides of a rectangle.
Step 2. Let <em>w</em> equal the width.
Step 3. Let <em>w+3</em> equal the length.
Step 4. Then you'll have this really confusing equation: P=w+w+w+3+w+3=4w+6=30
And it will give you <em>w= 6</em>
</span>
7/8, 1 is also 8/8 so if you add that to -1/8 (then it automatically subtracts since it’s adding a negative) making 7/8.
It’s -1 they are subjecting by 2
