Well, parallel lines have the same exact slope, so hmmm what's the slope of the one that runs through <span>(0, −3) and (2, 3)?
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so, we're really looking for a line whose slope is 3, and runs through -1, -1
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![\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ % (a,b) &&(~ -1 &,& -1~) \end{array} \\\\\\ % slope = m slope = m\implies 3 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=3[x-(-1)] \\\\\\ y+1=3(x+1)](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%26%28~%20-1%20%26%2C%26%20-1~%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%25%20slope%20%20%3D%20m%0Aslope%20%3D%20%20m%5Cimplies%203%0A%5C%5C%5C%5C%5C%5C%0A%25%20point-slope%20intercept%0A%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%5Cimplies%20y-%28-1%29%3D3%5Bx-%28-1%29%5D%0A%5C%5C%5C%5C%5C%5C%0Ay%2B1%3D3%28x%2B1%29)
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3x + 4y + 8 = 0
4y = -3x - 8
y = -3/4x - 2....slope here is -3/4. A parallel line will have the same slope.
y = mx + b
slope(m) = -3/4
y int (b) = 4
so ur equation is : y = -3/4x + 4
Hope this helps you out 3w+7=8
The answer is w= 1/3
Step by step:
3w+7=8
Step 1: is subtract is 7 from both sides.
3w+7-7=8-7
3w=1
Step 2: Divide both sides by 3.
3w/3 = 1/3
Your solution is:
w=1/3
3.4+0.4+4.17=7.97 you just have to try different combinations of different numbers with the decimals.
Answer:
y=2x+y-int
Step-by-step explanation:
If the line is parallet to the defined by the given equation the slope of the unknown line is m=2.
Use this value of slope to calculate the y intercept. 2 = ( 2 - y-int)/4 - 0)
THus, your equation is y = 2x + y-int
