Answer:
The answer to the question is;
The probability that there are exactly 4 successes or exactly 4 failures in the 13 rolls is 
.
Step-by-step explanation:
The probability of success = 1/2 =
probability of failure = 1/2
Since we have 4 success we then have 9 failures and the given probability can be solved as ₁₃C₄ × 1/2ⁿ×1/2¹³⁻ⁿ
Therefore we have
₁₃C₄ × 1/2⁴×1/2⁹ = 715/8192
That is the probability that there are exactly 4 successes or exactly 4 failures in the 13 rolls = 715/8192.
<span>f '(x) = [(-40x +11)(7x - 9) - 7(-4x +3)(5x + 1)]/(7x - 9)2</span>
<span>= [(-280x2<span> + 360x + 77x - 99) - 7(-20x</span>2<span> - 4x + 15x + 3)]/(7x - 9)</span>2</span>
<span>= [(-280x2<span> + 437x - 99) + (140x</span>2<span> + 28x - 105x - 21)]/(7x - 9)</span>2</span>
<span>= (-140x2<span> +360x - 120)/(7x - 9)</span><span>2
</span></span>
i think thats how you would solve it
hope this helps tho:)
$e\cdot e^x -e^{-2}=-2$
$\implies e^{x+1}=e^{-2}-2$
note that RHS is negative. (because e with negative exponent is less than 1)
and LHS is always positive.
so there cannot be any solution
15-3b=63
subtract 15 from both sides
-3b=48
divide -3 from both sides
b= -16
