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Novosadov [1.4K]
3 years ago
13

Which two reactions are also redox reactions?

Biology
1 answer:
Aleksandr [31]3 years ago
5 0

Answer:

The correct answer is synthesis and decomposition.

Explanation:

Redox reaction is a type of reaction where oxidation and reduction occur simultaneously.Both synthesis and decomposition belongs to the family of redox reaction.

For example

6CO2+12H2O=C6H12O6+6O2+6H2O

The above reaction is a synthesis reaction that occur during photosynthesis.It is a redox reaction because in this reaction carbon dioxide(CO2) is reduced to glucose(C6H12O6) and the water(H2O) molecule is oxidized to form oxygen(O2).

C6H12O6+6O2=6CO2+6H2O+Energy

The above reaction is a decomposition reaction that occurs during aerobic respiration.it is also a redox reaction because in this reaction glucose molecule is being oxidized to form carbon dioxide and the oxygen molecule is reduced to generate water.

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Answer:

In biology, the relationship in which one organism lives inside another is described by the term endosymbiosis.

Explanation:

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An example of endosymbiosis is found in bacteria that are part of the intestine of some living organisms, contributing to the process of food degradation.

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A firefighter wakes in the middle of the night to the sound of an alarm. it is likely that her _____ gland(s) are releasing the
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3 years ago
The stems of bamboo, a tropical grass, can grow at the phenomenal rate of 0.3 m/day under optimal conditions. Given that the ste
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Answer:

Approximately 6944 glucose residues are added enzymatically per second

Explanation:

Cellulose is the main structural polysaccharides in plants. It is composed of unbranched glucose monomer units linked to each other by beta 1-4 glycosidic bonds.

The cell wall and stem of plants cells are composed of cellulose fibers. They provide rigidity and support to the plant.

In the given bamboo plant, the enzymatic addition of glucose units to the growing cellulose fiber chains results in the phenomenal growth rate of the bamboo stem.

Since each glucose unit contributes ~0.5 nm to the length of a cellulose molecule, number of glucose units required for daily growth is calculated as follows:

0.5 nm = 10⁻⁹

0.3 m/0.5 x 10⁻⁹ m = 600000000 units of glucose per day

Number of seconds in a day = 24 * 60 * 60 = 86400 seconds

Number of glucose residues added per second = 600000000/86400

Number of glucose residues added per second = 6944.4 glucose molecules per second

Therefore, approximately 6944 glucose residues are added per second

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3 years ago
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