Answer:
-5, - 2, 3
Step-by-step explanation:
y=2x+3, y=-7, x=-5; y=-1, x=-2, y=9, x=3
Answer:
Try (
−
∞
,
∞
)
Step-by-step explanation:
OK so, I copied and pasted that so try to put it together lol
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer: A single word from white men was enough
against all our wishes etc.
Step-by-step explanation:
against their wishes they were separated ( yeah i'm right )
Answer:
VW=36
VT=27
Step-by-step explanation:
VW is the midsegment of the triangle
so
VW=72/2
=36
VXT is a right angle triangle
so
a²+b²=c²
a=√c²-b²
a=√45²-36²
a=√(45-36)(45+36)
a=√9×81
a=√9×√81
a=27
therefore
VT=27
