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slavikrds [6]
3 years ago
5

Kelly works two jobs. She usually works at a retail store for 8 hours during the day and is paid $12.90 per hour by the store. I

n the evening she works at a restaurant as a manager for 4 hours and is paid $12.20 per hour. How much does she make on average per hour for the day?
Mathematics
1 answer:
quester [9]3 years ago
6 0

Answer:

i believe its 12.55

Step-by-step explanation:

if you add both number,  12.90 and 12.20, then divide by 2.

you'll will gain the same result

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I need help with finding the limit for problem #1. I've already solved 2-4 I just don't get the first one.
emmainna [20.7K]
Answer: 9

-------------------------------------------

Look at the graph of f(x). Locate x = 3 on the graph and move to the left of that location. If you get closer and closer to x = 3 from the left side, then you approach y = 3

Do the same for g(x) as well. If you approach x = 3 from the left, then you approach y = 3. It does not matter there is a discontinuity here as we're only worried about approaching x = 3 from the left and not actually getting to that specific x value. 

We multiply those y values to get 3*3 = 9 as the answer

7 0
3 years ago
Please answer and explain
Ludmilka [50]

Answer:

C

Step-by-step explanation:

They are trying to deceive you into not choosing the star that is largest when written as 10^17.

When you rewrite the givens so that the power is 10^17 then the table will look like this.

1.76 * 10^17

2.213 * 10^17

3.142 * 10^17

1.255 * 10^14

It obviously isn't D.

It should be C

7 0
3 years ago
why do we need imaginary numbers?explain how can we expand (a+ib)^5. finally provide the expanded solution of (a+ib)^5.(write a
zheka24 [161]

Answer:

a. We need imaginary numbers to be able to solve equations which have the square-root of a negative number as part of the solution.

b. (a + ib)⁵ = a⁵ + 5ia⁴b - 10a³b² - 10ia²b³ + 5ab⁴ + ib⁵

Step-by-step explanation:

a. Why do we need imaginary numbers?

We need imaginary numbers to be able to solve equations which have the square-root of a negative number as part of the solution. For example, the equation of the form x² + 2x + 1 = 0 has the solution (x - 1)(x + 1) = 0 , x = 1 twice. The equation x² + 1 = 0 has the solution x² = -1 ⇒ x = √-1. Since we cannot find the square-root of a negative number, the identity i = √-1 was developed to be the solution to the problem of solving quadratic equations which have the square-root of a negative number.

b. Expand (a + ib)⁵

(a + ib)⁵ =  (a + ib)(a + ib)⁴ = (a + ib)(a + ib)²(a + ib)²

(a + ib)² = (a + ib)(a + ib) = a² + 2iab + (ib)² = a² + 2iab - b²

(a + ib)²(a + ib)² = (a² + 2iab - b²)(a² + 2iab - b²)

= a⁴ + 2ia³b - a²b² + 2ia³b + (2iab)² - 2iab³ - a²b² - 2iab³ + b⁴

= a⁴ + 2ia³b - a²b² + 2ia³b - 4a²b² - 2iab³ - a²b² - 2iab³ + b⁴

collecting like terms, we have

= a⁴ + 2ia³b + 2ia³b - a²b² - 4a²b² - a²b² - 2iab³  - 2iab³ + b⁴

= a⁴ + 4ia³b - 6a²b² - 4iab³ + b⁴

(a + ib)(a + ib)⁴ = (a + ib)(a⁴ + 4ia³b - 6a²b² - 4iab³ + b⁴)

= a⁵ + 4ia⁴b - 6a³b² - 4ia²b³ + ab⁴ + ia⁴b + 4i²a³b² - 6ia²b³ - 4i²ab⁴ + ib⁵

= a⁵ + 4ia⁴b - 6a³b² - 4ia²b³ + ab⁴ + ia⁴b - 4a³b² - 6ia²b³ + 4ab⁴ + ib⁵

collecting like terms, we have

= a⁵ + 4ia⁴b + ia⁴b - 6a³b² - 4a³b² - 4ia²b³ - 6ia²b³ + ab⁴ + 4ab⁴ + ib⁵

= a⁵ + 5ia⁴b - 10a³b² - 10ia²b³ + 5ab⁴ + ib⁵

So, (a + ib)⁵ = a⁵ + 5ia⁴b - 10a³b² - 10ia²b³ + 5ab⁴ + ib⁵

5 0
3 years ago
1. Subtract. 9 1/3-1 2/3 = ? Explain how you got the answer.
AleksAgata [21]
My answer is 8 5/9
First, you have to multiply the denominators to get your least common denominator.
Second, you have to multiply the numerators and the denominators together to get two different fractions with the same denominator. You should get 9 3/9 and 1 6/9.

Your answer should be 8 5/9
8 0
3 years ago
What values are solutions of 0 =2xexponent of 2 -6x-8
Svetlanka [38]

Answer:

x = -1 and x = 4

Step-by-step explanation:

Firstly solve the quadratic expression of

2x^2-6x-8 = 0....it gives you the two brackets of.....(2x-8)(x+1)=0

then...you equate the two brackets to 0.separately

2x-8 = 0....which gives you...x = 4...as the first solution..then..;

x+1 = 0....which gives you...x = -1...as the second solution

3 0
3 years ago
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