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belka [17]
2 years ago
11

PLZ ANSWER THIS QUICK! THANK U!!

Mathematics
1 answer:
vampirchik [111]2 years ago
4 0
There is 33 students in the class
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3w-4z=8<br> 2w+3z=-6 solve
marissa [1.9K]

Answer:

W = 0

Z = -2

Step-by-step explanation:

While simplyfying the equation, i noticed that one is 24 and the other is -24, which meant that one value is non existent, and after i found out that w = 0 imputing the reslut made that easier

4 0
2 years ago
Solve this please with an explanation of process your finding the values of x and y
SpyIntel [72]

Congruent sides, so isosceles triangle.  When we have an isosceles triangle the bisector of angle A is a perpendicular bisector of BC with foot D.   So x=ADB=90 degrees.

Angle B is 47 degrees and angle y=BAD is complementary, the other acute angle in a right triangle.

y = 90 - 47 = 43

Answer: x=90, y=43

4 0
3 years ago
-2p + 7= 11 i need a answer know pleas help me
siniylev [52]

Answer:

p= -3/2 or p= -1 1/2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
2 years ago
Which scenario is best represented by the equation y = 8x?
harkovskaia [24]

Answer:

The answer is A.

Step-by-step explanation:

6 0
3 years ago
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