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Dafna1 [17]
3 years ago
7

Find the empirical and molecular formula for a molar mass of 60.10g/mol; 39.97% carbon 13.41% hydrogen: 46.62% nitrogen

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
5 0
Assuming we have 100g, this means that

39.97g Carbon * 1 mol / 12 g = 3.33 mol Carbon
13.41g Hydrogen * 1 mol/1 g = 13.41 mol Hydrogen
46.62g Nitrogen * 1 mol / 14 g = 3.33 mol Nitrogen
Dividing everything by 3.33, we get

1 mol Carbon, 4.03 mol Hydrogen, 1 mol Nitrogen.

Empirical formula is CH4N

<span>The mass of the empirical formula is
12 + 4 + 14 = 30

Since the molar mass is double, we multiply all our subscripts

The molecular formula is C2H8N2

The answers to this question are </span><span>an empirical formula of CH4N</span> and a molecular formula of C2H8N2 .
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Electrochemistry - Equilibrium
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Answer:

Explanation:

The relation between equilibrium constant and Ecell is given below .

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n = 2

Putting the values

.25 = (8.314 x 298  lnK) / (2 x 96485 )

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K = 2.85 x 10⁸

2 )

Change in free energy Δ G

Δ G ⁰ = nE⁰ F

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3 )

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K = 1.62 x 10⁶⁰

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3 years ago
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