The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
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Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.
<h3>What is a z-distribution confidence interval?</h3>The confidence interval is:
The margin of error is:
In which:
Assuming an uniform distribution, the standard deviation is given by:
In this problem, we have a 95% confidence level, hence, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The sample size is found solving for n when the margin of error is of M = 0.006, hence:
n = 142,282.
A sample of 142,282 should be taken, which is not practical as it is too large of a sample.
More can be learned about the z-distribution at brainly.com/question/25890103
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