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2 years ago

Can someone help me with this?

Mathematics

1 answer:

JulijaS [17]2 years ago

8 0

1: No (It cannot flip to match the other side [there is a term for it...])
2: No (It cannot flip to match the other side)
3: Yes (It can flip to match the other side)
4. No (It cannot flip to match the other side)
5. No (It isn't attached so it can't flip, anyway)
6. No (It cannot flip to match the other side)

I don't know 100%, but I think these are the answers...
You may have the vocab for the "flip-to-match" thing...

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3 years ago

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3 years ago

A bag contain 5 red marbles,4 green marbles and 1 blue marble. A marble is chosen at random from the bag and not replaced; then

jarptica [38.1K]

Answer:

$\frac{2}{15}$

Step-by-step explanation:

GIVEN: A bag contain $5$ red marbles, $4$ green marbles and $1$ blue marble. A marble is chosen at random from the bag and not replaced, then a second marble is chose.

TO FIND: What is the probability both marbles are green.

SOLUTION:

Total marbles in bag $=10$

total number of green marbles $=4$

Probability that first marble will be green $P(A)=\frac{\text{total green marbles}}{\text{total marbles}}$

$=\frac{4}{10}=\frac{2}{5}$

Probability that second marble will be green $P(B)=\frac{\text{total green marble in bag}}{\text{total marble in bag}}$

$\frac{3}{9}=\frac{1}{3}$

As both events are disjoint

probability both marbles are green $=P(A)\times P(B)$

$=\frac{2}{5}\times\frac{1}{3}=\frac{2}{15}$

Hence the probability both marbles are green is $\frac{2}{15}$

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3 years ago

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Equal sets have the exact same elements, so they must have the same number of elements. Therefore, equal sets must also be equivalent. No, not all equivalent sets are also equal sets

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