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Yuki888 [10]
3 years ago
9

a) What is the probability that a person selected at random from the general population is senior citizen who will get the flu t

his season?
Mathematics
1 answer:
Greeley [361]3 years ago
7 0
<span>The probability that a person selected at random from the general population is senior citizen who will get the flu this season is 0.14 x 0.18 = 0.0252</span>
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I need to know the slope of the line given the two points
Karo-lina-s [1.5K]
Slope=(y2-y1)/(x2-x1)
=(4-7)/(2--3)
=3/5

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3 years ago
What is workers compensation? ​
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Insurance providing salary to employees injured while working.
6 0
3 years ago
For the figure below, name each of the following:
11111nata11111 [884]

Answer:

PM is radius

NL is diameter

LM is chord

LJ is secant

NJ is tangent

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7 0
3 years ago
Could you help me with this. <br><br> Express in simplest radical form.<br> 162<br><br> ​
Ivanshal [37]

Answer:

The square root of 162 in its simplest form means to get the number 162 inside the radical √ as low as possible.

Here is how to do that! First we write the square root of 162 like this:

√162

The largest perfect square of the factors of 162 is 81. We can therefore convert √162 like this:

√81 × 2

Next, we separate the numbers inside the √ as such:

√81 × √2

√81 is a perfect square that equals 9. We can therefore put 9 outside the radical and get the final answer to square root of 162 in simplest radical form as follows:

9√2

Step-by-step explanation:

7 0
3 years ago
The mean annual income for adult women in one city is $28,520 and the standard deviation of the incomes is $5600. The distributi
pshichka [43]

Answer:

E(\bar{x}) = 28520

Standard error of mean = 689

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $28,520

Standard Deviation, σ = $5600

Mean of sampling distribution =

E(\bar{x}) = \mu = 28520

As per Central Limit Theorem, if the sample size is large enough, then the sampling distribution of the sample means follow approximately a normal distribution.

Sample size, n = 66

Since the sample size is large, we can use normal distribution for approximation.

Standard error of mean =

\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{5600}{\sqrt{66}} = 689.31 \approx 689

7 0
3 years ago
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