The equation of a circle:
(h, k) - center
r - radius
Look at the picture:
center: (4, -2) → h = 4, k = -2
radius: r= 5
Substitute:
Answer:
100%
Step-by-step explanation:
Probability of a product showing up in warehouse A =60%
Probability of a product showing up in warehouse B = 80%
Probability of 2 product showing up in warehouse A is
Probability of 1 product showing up in A and probability of 1 product showing up in A
A n A = 60% x 60% = 0.6 x 0.6 = 0.36 =36%
Probability of 2 product showing up in warehouse B is
Same as above
Probability of 1 product showing up in B and probability of 1 product showing up in B
B n B = 80% x 80% = 0.8 x 0.8 = 0.64= 64%
Probability of 2 product showing up in same warehouse is define as
Probability of 1 product showing up in A and probability of 1 product showing up in A or
Probability of 1 product showing up in B and probability of 1 product showing up in B
(AnA) U (BnB) =
36% + 64% = 0.36 + 0.64= 1
100%
Answer:
Answer in image below
Step-by-step explanation:
Answer:
P(4≤x≤7) = 2/3
Step-by-step explanation:
We'll begin by obtaining the sample space (S) i.e possible outcome of rolling both dice at the same time. This is illustrated below:
1,1 1,2 1,3 1,4 1,5 1,6
2,1 2,2 2,3 2,4 2,5 2,6
3,1 3,2 3,3 3,4 3,5 3,6
4,1 4,2 4,3 4,4 4,5 4,6
5,1 5,2 5,3 5,4 5,5 5,6
6,1 6,2 6,3 6,4 6,5 6,6
Adding the outcome together, the sample space (S) becomes:
2 3 4 5 6 7
3 4 5 6 7 8
4 5 6 7 8 9
5 6 7 8 9 10
6 7 8 9 10 11
7 8 9 10 11 12
Next, we shall obtain the event of 4≤x≤7. This is illustrated below:
4 5 6 7
4 5 6 7
4 5 6 7
4 5 6 7
4 5 6 7
4 5 6 7
Finally, we shall determine P(4≤x≤7). This can be obtained as follow:
Element in the sample space, n(S) = 36
Element in 4≤x≤7, n(4≤x≤7) = 24
Probability of 4≤x≤7, P(4≤x≤7) = ?
P(4≤x≤7) = n(4≤x≤7) / nS
P(4≤x≤7) = 24/36
P(4≤x≤7) = 2/3
Answer:
The smaller number is 5.
The bigger number is 15.
Step-by-step explanation:
Let the smaller number be x and the bigger number be x+10.
x+x+10 = 4x
2x+10 = 4x
10 = 4x-2x
2x = 10
x = 10÷2
= 5
x+10 = 5+10
= 15
