Hello there!
y + 15 < 3
Start by subtracting 15 on both sides
y + 15 - 15 < 3 - 15
y < -12
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Answer:
2
Step-by-step explanation:
4x = 32 - x2 would be much clearer if written as 4x = 32 - x^2. Please use
" ^ " to indicate exponentiation.
Rewrite 4x = 32 - x^2 in the standard form of a quadratic: x^2 + 4x - 32
Then the coefficients are a = 1, b = 4 and c = -32.
Find the discriminant. It is b^2-4ac.
Here, b^2-4ac = 4^2 - 4(1)(-32), or 16 + 128, or 144.
Because the discriminant is positive, we know immediately that this quadratic has two real, unequal roots.
So, the answer to this question is "the graph of 4x = 32 - x^2 cross the x-axis in two places."
Answer:
Step-by-step explanation:
This is a duplicate of one I have done for you
BF = 3*HF
BF = 3*6
BF = 18
Eliminate y's
multiply second equaiton by 4
4x+4y=-4
add to first equation
3x-4y=-24
<u>4x+4y=-4 +</u>
7x+0y=-28
7x=-28
divide both sides by 7
x=-4
sub back
x+y=-1
-4+y=-1
add 4 to both sides
y=3
(x,y)
(-4,3)
D is answer