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erastovalidia [21]
3 years ago
7

Point P is the center of dilation. Triangle S T U is dilated to create triangle S prime T prime U prime. The length of P T is 2.

The length of T T prime is 10.
Which statements justify that the dilation of triangle STU is an enlargement increasing its size by the magnitude of the scale factor? Select two options.

The triangle pre-image is closer to the point of dilation than the image.
The triangle image is closer to the point of dilation than the pre-image.
The value of the scale factor, One-sixth, is between 0 and 1.
The value of the scale factor, 6, is greater than 1.
The vertices of the pre-image are collinear with the vertices of the image.
Mathematics
2 answers:
Stels [109]3 years ago
6 0

Answer:

A and D

Step-by-step explanation:

i took the quiz

kvasek [131]3 years ago
4 0

Answer:

A and D

Step-by-step explanation:

edge2021

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At a school there are 864 students and 80 staff members. 5/8 of the students are boys. How many girls are in the school?
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Answer:

354

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3/8 multiplied by 864

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Oduvanchick [21]

Answer:

30 degrees

Step-by-step explanation:

To figure out theta is using a bit of simple trigonometry.

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= sin(theta) = 0.5

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2 years ago
How many 4 digit multiples can not be divided by 5
Advocard [28]

Answer:

1800

Step-by-step explanation:

Let us solve this question by Modular Airthmatic.

Let the lowest 4 digit number be X.

X= 1 (mod 5)

X =2 (mod 5)

X=3 (mod 5)

X =4 (mod 5)

X=1+5 t where t is any integer.

1+5 t=2 (mod 5)

5 t=1 (mod 5 )

5 is the Modular Inverse of modulo 5

t=1 (mod 5)

t =1+5 u : u= any integer.

X becomes 1+ 5 (1+5u )=6+25 u

6+25u =3 (mod 5)

25 u= -3 (mod 5)=2 (mod 5)

25 is Modular Inverse of Modulo 5

u=2 (mod 5)

u =2+5 v : v= any integer.

X becomes 6 +25 (2+5 v)=56+125 v .

56 +125 v=4 (mod 5)

125 v=-52 (mod 5)=3 (mod 5)

125 is Modular Inverse of modulo 5

v = 3 (mod 5)

v =3 +5 w where w is any integer.

For lowest 4 digit number, take

w=200

X=1003 : Lowest 4 digit number.

Take w=201

X=208 : Next number.

For 4 digit largest number, take

w=1995

X= 9978 : Largest number.

No. of Numbers =(1995 - 200 )+1=1800 □Ans.

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3 years ago
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The teacher handed out 6 copies

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