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Lady bird [3.3K]
4 years ago
7

On a map of Arizona, the scale is 1 inch = 5 inches. The distance between Brady's house and Flagstaff is 23 inches on the map. W

hat is the actual distance between Brady's house and Flagstaff.​
Mathematics
1 answer:
sladkih [1.3K]4 years ago
7 0

So we know that 1 inch on the map = 5 inches.

So if Brady's house is 23 inches away from Flagstaff on the map:

23 * 5 = 115.

So 115 inches is the actual distance...

Wait. His house is 9 feet away from Flagstaff? That's cool.

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List the markup and retail price of each item. Round to two decimal places when necessary. A shirt item price is $33.75 and the
kifflom [539]

Answer:

markup price = $25.31

retail price = $59.06

Step-by-step explanation:

Markup price is 75% OF 33.75

Retail price is original price (33.75) PLUS the markup price (to be found)

Firstly, converting a percentage to a decimal is simple. We simply divide by 100. So:

75% = 75/100 = 0.75

Now, to find markup, we multiply:

33.75 * 0.75 = $25.31

Now, the retail price is SUM of original and markup, that would be:

retail price = 33.75 + 25.31 = $59.06

Thus,

markup price = $25.31

retail price = $59.06

4 0
4 years ago
Please Help!! Will pick brainliest!
leonid [27]
Small circle 2/4 = 1/2 and the big circle is 3/5 i hope this is correct. im truly sorry if this was wrong
7 0
3 years ago
Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (3, 1, 0) and perpendicu
iren2701 [21]

Answer with Step-by-step explanation:

We are given that a point (3,1,0)

Two vectors are

A=<1,1,0>

B=<0,1,1>

A\times B=\begin{vmatrix}i&j&k\\1&1&0\\0&1&1\end{vmatrix}

A\times B=i-j+k

Let v=A\times B=i-j+k

v==

r_0==

r=r_0+vt

Substitute the values then we get

r=+t

r=

The parametric equation of the line

x=x_0+at,y=y_0+bt,z=z_0+ct

Using the formula

The parametric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by

x=3+t,y=1-t,z=t

The symmetric equation of the line is given by

\frac{x-x_0}{a}=\frac{y-y_0}{b}=\frac{z-z_0}{c}

Using the formula

The symmetric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by

\frac{x-3}{1}=\frac{y-1}{-1}=z

8 0
4 years ago
What is the slope of the line that contains these points?
coldgirl [10]

Answer:

Step-by-step explanation:

7 0
3 years ago
Given f(x) = 4+1 , describe how the graph of g compares with compares with the graph of f?
ycow [4]

<em>I think you wrote an incomplete question. With a little research, I was able to find a question similar to you which is attached below. So, I would solve your question based on the question attached below, which anyways would clear your concept. </em>

Answer:

g(x) is the graph of f(x) translated left 3 units. Also, the comparison graph is attached below.

Step-by-step explanation:

Considering the complete question attached below

Given the function

f\left(x\right)\:=\:4x+1

As for g(x)=f(x-h), the graph of g(x) is the graph of f(x) translated right h units when 'h' is greater than zero, and left | h | units when h is lesser than zero.

so it is clear if  

g(x)=4(x+3)+1 and f\left(x\right)\:=\:4x+1, then g(x) = f(x+3).

Hence, h = -4 ( lesser than zero i.e. h < 0).

Therefore, g(x) is the graph of f(x) translated left 3 units. Also, the comparison graph is attached below.

5 0
3 years ago
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